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3 years ago

Who do you think needs a higher level of education, a police officer or a lawyer?

2 answers:

7 0

A lawyer need more education,since they mostly do everything like cases,crimes they will have to work on law enforcement etc.

ehidna [41]3 years ago

4 0

A lawyer, I believe they have to go to school for longer.

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Diana and Kinsey are put in charge of choosing a mascot for their basketball team. There are fifteen players on the team, but Di

arsen [322]

Answer:

the data are inadequate

Explanation:

If there are 15 people on the team, and only five have been asked about the mascot, this means the data collecting is wrong, and the result doesn’t include thoughts of the majority. If Diana and Kinsey want to have adequate data, they should ask as many as possible, if not all players in the team. This would truly show what the majority wants meaning it will show what the team wants. This kind of complete data correcting is the correct one.

6 0

3 years ago

A compressor operates at steady state with Refrigerant 134a as the working fluid. The refrigerant enters at 0.24 MPa, 0°C, with

marissa [1.9K]

Answer:

POWER INPUT = 82.989 KW

Explanation:

For pressure P =0.24 MPa and T_1 = 0 DEGREE, Enthalapy _1 = 248.89 kJ/kg

For pressure P =1 MPa and T_1 = 50 DEGREE, Enthalapy _1 = 280.19 kJ/kg

Heat loss Q = 0.05w

Inlet diameter = 3 cm

exit diamter = 1.5 cm

volume of tank will be v = area * velocity

velocity at inlet $= \frac{0.64\60 m/s}{ \frac{\pi}{4} (3\times 10^{-2})^2} = 15.09 m/s$

velocity at outlet $= \frac{0.64\60 m/s}{ \frac{\pi}{4} (1.5\times 10^{-2})^2} = 60.36 m/s$

steady flow energy equation

$E_{IN} = E_{OUT}$

$h_1 + \frac{v_1^2}{2g} +wc = h_2 + \frac{v_2^2}{2g} + 0.05wc$

$248.89 + \frac{15.09^2}{2} + wc = 280.18 + \frac{60.36^2}{2} + 0.05 wc$

solving wc = 1830.64 kJ/kg

wc in KWH

we know that $wc = \dot m wc$

$\dot m = 4.25 kg/m3 \times (0.64/60) m^3/s$

$\dot m = 0.04533 kg/s$

$wc = 0.04533 \times 1830.64 = 82.989 kW$

5 0

4 years ago

Why efficiency of gas turbines are lower than combustion engine

xxTIMURxx [149]

The performance of power plants at partial load has become a significant operational consideration for electric power grids worldwide. This technical comparison examines the range of output and the part load efficiency of combustion engines and gas turbines, and how Wärtsilä power plants deliver enhanced flexibility.

7 0

3 years ago

Read 2 more answers

Info security:

il63 [147K]

Answer:

True

Explanation:

Dual home host - it is referred to as the firewall that is incorporated with two or more networks. out of these two networks, one is assigned to the internal network and the other is for the network. The main purpose of the dual-homed host is to ensure that no Internet protocol traffic is induced between both the network.

The most simple example of a dual-homed host is a computing motherboard that is provided with two network interfaces.

7 0

4 years ago

Refrigerant 134a vapor in a piston-cylinder assembly undergoes a process at constant pressure from an initial state at 8 bar and

jonny [76]

Answer:

- Work done is 2.39 kJ

- heat transfer is 20.23 kJ/kg

Explanation:

Given the data in the question;

First we obtain for specific volumes and specific enthalpy from "Table Properties Refrigerant 134a;

Specific Volume v₁ = 0.02547 m³/kg

Specific enthalpy u₁ = 243.78 kJ/kg

Specific Volume V₂ = 0.02846 m³/kg

Specific enthalpy u₂ = 261.62 kJ/kg

p = 8 bar = 800 kPa

Any changes in kinetic and potential energy are negligible.

So we determine the work done by using the equation at constant pressure

]Work done W = p( v₂ - v₁ )

we substitute

W = 800 kPa( 0.02846 m³/kg - 0.02547 m³/kg )

W = 800 kPa( 0.00299 m³/kg )

W = 2.39 kJ

Therefore, Work done is 2.39 kJ

Heat transfer;

using equation at constant pressure

Heat transfer Q = W + ( u₂ - u₁ )

so we substitute

Q = 2.392 kJ + ( 261.62 kJ/kg - 243.78 kJ/kg )

Q = 2.392 kJ + 17.84 kJ/kg )

Q = 20.23 kJ/kg

Therefore, heat transfer is 20.23 kJ/kg

3 0

3 years ago