As we know that, f=ma where
f= net force
m=mass of body
a=acceleration
Substitute m and a in the formula and you will get the answer
Answer:
Explanation:
Given
diameter 
density 
frequency 
Length of silk strand 
Velocity in the string is as follows

The expression for Fundamental Frequency




Squaring




Answer:
Time period of oscillation on moon will be equal to 3.347 sec
Explanation:
We have given mass which is attached to the spring m = 3.42 kg
Spring constant K = 12 N/m
We have to find the period of oscillation
Period of oscillation is equal to
, here m is mass and K is spring constant
So period of oscillation 

So time period of oscillation will be equal to 3.347 sec
As it is a spring mass system and from the relation we can see that time period is independent of g
So time period will be same on earth and moon
Answer:
3.085 [m].
Explanation:
1) The rule:
m₁*g*l₁=m₂*g*l₂, where m₁ and l₁ - the mass and distance for the small child, m₂ and l₂ - for the big child;
2) according to the condigion l₁+l₂=5, then
3) it is possible to make up the system:

4) finally, l₁=145/47≈3.085 [m].
Answer: 9/10
Explanation:
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