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3 years ago

Work is a product of ___________.

Physics

2 answers:

swat323 years ago

6 0

hey buddy here is your answer:

work is a product of force and distance

explanation:

according to physics,work is said to be done when there is displacement in the direction of force

si unit:joule(j)

alexgriva [62]3 years ago

4 0

The correct option is D

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Answer:

The cytoplasm holds all the organelles, except the nucleus.

Explanation:

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3 years ago

I need help with this

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2 years ago

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3 years ago

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Com que rapidez estará sendo feito trabalho elétrico num resistor de 10 ohms, percorrido por uma corrente elétrica de 5 A? Qual

34kurt

Poder = (resistencia) x (corrente)²

Poder = (10 ohms) x (5 A)²

Poder = 250 watts (250 Joule por segundo)

2 horas = 7,200 segundos

Energia = (250 joule/seg) x (7,200 seg)

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3 years ago

An 20-cm-long Bicycle Crank Arm. With A Pedal At One End. Is Attached To A 25-cm-diameter Sprocket, The Toothed Disk Around Whic

malfutka [58]

To solve the problem, it is necessary to apply the concepts related to the kinematic equations of the description of angular movement.

The angular velocity can be described as

$\omega_f = \omega_0 + \alpha t$

Where,

$\omega_f =$ Final Angular Velocity

$\omega_0 =$ Initial Angular velocity

$\alpha =$ Angular acceleration

t = time

The relation between the tangential acceleration is given as,

$a = \alpha r$

where,

r = radius.

PART A ) Using our values and replacing at the previous equation we have that

$\omega_f = (94rpm)(\frac{2\pi rad}{60s})= 9.8436rad/s$

$\omega_0 = 63rpm(\frac{2\pi rad}{60s})= 6.5973rad/s$

$t = 11s$

Replacing the previous equation with our values we have,

$\omega_f = \omega_0 + \alpha t$

$9.8436 = 6.5973 + \alpha (11)$

$\alpha = \frac{9.8436- 6.5973}{11}$

$\alpha = 0.295rad/s^2$

The tangential velocity then would be,

$a = \alpha r$

$a = (0.295)(0.2)$

$a = 0.059m/s^2$

Part B) To find the displacement as a function of angular velocity and angular acceleration regardless of time, we would use the equation

$\omega_f^2=\omega_0^2+2\alpha\theta$

Replacing with our values and re-arrange to find $\theta,$

$\theta = \frac{\omega_f^2-\omega_0^2}{2\alpha}$

$\theta = \frac{9.8436^2-6.5973^2}{2*0.295}$

$\theta = 90.461rad$

That is equal in revolution to

$\theta = 90.461rad(\frac{1rev}{2\pi rad}) = 14.397rev$

The linear displacement of the system is,

$x = \theta*(2\pi*r)$

$x = 14.397*(2\pi*\frac{0.25}{2})$

$x = 11.3m$

5 0

3 years ago