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3 years ago

Which is a vector quantity speed or velocity

1 answer:

8 0

Velocity is a vector quantity. A vector quantity has both a magnitude and a direction. Speed only has a magnitude, but no direction. Velocity has both.

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zhannawk [14.2K]

Average speed= total distance/total time =12km/h

6 0

3 years ago

What would happen to a satellite if it’s orbit speed was reduced by half? Also how about if it doubled?

weeeeeb [17]

For finding the orbital speed of the satellite we can say that the centripetal force for the circular motion of satellite is provided by the gravitational force of earth

so here we can say

$F_g = \frac{mv^2}{r}$

$\frac{GMm}{r^2} = \frac{mv^2}{r}$

now we will have

$v = \sqrt{\frac{GM}{r}}$

now here we will say that orbital speed of the satellite is inversely depends on the orbital radius

So here if orbital speed is half then as per above relation we can say that orbital distance will become four times

Also we can say that if orbital speed is double then orbital distance will become one fourth of initial distance.

7 0

3 years ago

What methods can be used to break down substances into elements

pychu [463]

Well i think Hydrolysis - using water to split a molecule that has formed via a condensation

8 0

3 years ago

1. A pendulum has a period of 3 seconds. What's its frequency? 2. A pendulum has a frequency of 0.25 Hz. What's its period? 3. A

RideAnS [48]

Answer:

(1) 0.333 Hz

(2) 4 sec

(3) 2 sec, 0.5 Hz

Explanation:

(1) We have given time period of pendulum is 3 sec

So T = 3 sec

Frequency will be equal to $f=\frac{1}{T}=\frac{1}{3}=0.333Hz$

(2) Frequency of the pendulum is given f = 0.25 Hz

Time period is equal to $T=\frac{1}{f}=\frac{1}{0.25}=4sec$

(3) It is given that a pendulum makes 10 back and forth swings in 20 seconds

So time taken to complete 1 back and forth swings = $=\frac{20}{10}=2sec$

So time period T = 2 sec

Frequency will be equal to $f=\frac{1}{T}=\frac{1}{2}=0.5Hz$

6 0

3 years ago

Read 2 more answers

A 330-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,110 A. If the conductor is copper

vodka [1.7K]

Answer:

t = 402 years

Explanation:

To find the number of year that electrons take in crossing the complete transmission line, you first calculate the drift speed of the electrons. Then, you use the following formula for the current in a wire:

$I=nqv_dA$ (1)

n: number of mobile charge carrier per volume = 8.50*10^28 e/m^3

q: charge of the electron = 1.6*10^-19 C

vd: drift velocity of electron in the metal = ?

A: cross sectional area of the wire = π r^2 = π (0.02m/2)^2 = 3.1415*10^-4 m^2

I: current in the wire = 1110 A

You solve the equation (1) for vd:

$v_d=\frac{I}{nqA}=\frac{110A}{(8.50*10^{28}m^{-3})(1.6*10^{-19}C)(3.1415*10^{-4}m^2)}\\\\v_d=2.59*10^{-4}m/s$

Next, you calculate the time by using the information about the length of the line transmission:

$x=v_dt\\\\x=330km=330000m\\\\t=\frac{x}{v_d}=\frac{330000m}{2.59*10^{-4}m/s}=1,270,184,865s\\\\1,270,184,865s*\frac{1\ year}{3,156,107}=402.45\ years$

hence, the electrons will take aproximately 402 years in crossing the line of transmission

6 0

3 years ago