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Katarina [22]
3 years ago
11

What Is the [H+1] of 8.1•10-8

Chemistry
1 answer:
s2008m [1.1K]3 years ago
8 0
Using the Bronsted-Lowry (B/L) Theory tell which is the acid and which the base in .... (c) [H+<span>] = </span>8.1x10-10M [OH-] = 1x10-14/8.1x10-10<span> = 0.12x10</span>-4<span> = 1.2x10</span>-5M ... (c) [OH-] = 4.5x10-7M [H+] = 1x10-14/4.5x10-7<span> = 0.22x10</span>-7<span> = 2.2</span>x10<span>-8</span><span>M</span>
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Look at the diagram of the solar system.
arlik [135]

Answer:

Retrograde Motion

Explanation:

Geocentric model of planets was proposed by Ptolemy. It stated that all sun, planets and stars revolve round the earth in circular orbits.

NOTE: Ptolemy: an ancient astronomer, geographer, and mathematician who considered the Earth the center of the universe (the "Ptolemaic system").

8 0
3 years ago
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A certain protein was found to contain 0.292% manganese by mass. Determine the minimum molecular mass of the protein.
Lisa [10]
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4 0
3 years ago
Heyy pls help anyone?
madam [21]
1a. calcium chloride (CaCl2)
b. 2HCl (aq) + Ca(OH)2 (s) —> CaCl2 (aq) + 2H2O (l)

i’m not sure about the rest but i hope this helped ^^
7 0
3 years ago
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To how much water should 100 ml of 18m sulfuric acid be added to prepare a 1.5m solution
SashulF [63]

Answer:

Take 100 ml of a 18 molar solution. The total number of moles is (1 liter/1000 ml) 100 ml 18 moles is 1.8 moles.

1.5 moles in 1 liter so If 1.1 liters of water is added, the total volume is 1.2 liters and 1.8 moles are dissolves in it. 1.8 moles/ 1.2 liters is 1.5 moles per liter.

5 0
3 years ago
What is the molarity of a solution made with 64 grams of sodium hydroxide in 4 liters of water
ehidna [41]

Answer:

The molarity of the solution: 0,27M

Explanation:

First , we calculate the weight of 1 mol of NaCl:

Weight 1mol NaCl= Weight Na + Weight Cl= 23 g+ 35, 5 g= 58, 5 g/mol

58,5 g---1 mol NaCl

64 g--------x= (64 g x1 mol NaCl)/58,5 g= 1, 09 mol NaCl

A solution molar--> moles of solute in 1 L of solution:

4 L-----1,09 mol NaCl

1L----x0( 1L x1,09 mol NaCl)/4L =0,27moles NaCl--->0,27M

7 0
3 years ago
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