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Anika [276]
3 years ago
7

Draw the Lewis structure for BCl3. How many single bonds, double bonds, triple bonds, and unshared pairs of electrons are on the

central atom, in that order

Chemistry
1 answer:
andreev551 [17]3 years ago
3 0

Answer :  The number of single bonds, double bonds, triple bonds, and unshared pairs of electrons on the central atom are, 3, 0, 0 and 0 respectively.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, BCl_3

As we know that boron has '3' valence electrons and chlorine has '7' valence electrons.

Therefore, the total number of valence electrons in BCl_3 = 3 + 3(7) = 24

According to Lewis-dot structure, there are 6 number of bonding electrons and 18 number of non-bonding electrons.

From the Lewis-dot structure we conclude that,

The number of single bonds, double bonds, triple bonds, and unshared pairs of electrons on the central atom are, 3, 0, 0 and 0 respectively.

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How many milliliters of a 0.266 M RbNO3 solution are required to make 150.0 mL of 0.075 M RbNO3 solution? How many milliliters o
Westkost [7]

Answer : 42.3 ml of a 0.266 M RbNO_3 solution are required.

Solution : Given,

Molarity of RbNO_3 solution 1 = 0.266 M

Molarity of RbNO_3 solution 2 = 0.075 M

Volume of RbNO_3 solution 2 = 150 ml = 0.150 L      (1 L = 1000 ml)

Formula used :

M_1V_1=M_2V_2

where,

M_1 = Molarity of RbNO_3 solution 1

M_2 = Molarity of RbNO_3 solution 2

V_1 = Volume of RbNO_3 solution 1  

V_2 = Volume of RbNO_3 solution 2

Now put all the given values in above formula, we get

0.266M\times V_1=0.075M\times 0.150L\\V_1=0.042293L=42.293ml\approx 42.3 ml                 (1 L = 1000 ml)

Therefore, 42.3 ml of a 0.266 M RbNO_3 solution are required.

8 0
3 years ago
2. Write the formula or name for the following
Tems11 [23]

Answer:

Diphosphorus pentoxide

Carbon dichloride

BCl3

N2H4

Explanation:

These are all covalent compounds. To name covalent compounds, you add prefixes to the beginning of their names depending on what the subscript is of each element. The prefixes are:

1: Mono

2: Di

3: Tri

4: Tetra

5: Penta

6: Hexa

7: Hepta

8: Octa

9: Nona

10: Deca

For example, since the first one is Phopsphorus with a 2 next to it, you add the prefix Di to it.

If the first element in the compound only has one, meaning no number next to it, you do not say mono. This is why we just say "Carbon" for the second one instead of "Monocarbon."

Finally, you always have to end the second element in the compound with "ide." So, "chlorine" becomes "chloride," "oxygen" becomes "oxide," and so on.

7 0
3 years ago
The half-life for the radioactive decay of calcium-47 is 4.5 days. how many half-lives have elapsed after 27 days?
Evgesh-ka [11]
1 half-life      - 4.5 days
x half-lives   - 27 days

x=(1*27)/4.5=6
6 <span>half-lives have elapsed after 27 days.</span>
8 0
3 years ago
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Deffense [45]

Answer:

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Explanation:

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6 0
2 years ago
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Answer:

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7 0
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