Question

What is the theoretical yield of SO3 produced by 8.96 g of S?

Answer 1

Answer: Theoretical yield of $SO_3$ produced by 8.96 g of S is 33.6 g

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} S=\frac{8.96g}{32g/mol}=0.28moles$

The balanced chemical equation is:  

$2S+3O_2\rightarrow 2SO_3$  

According to stoichiometry :

2 moles of $S$ produce =  3 moles of $SO_3$

Thus 0.28 moles of $S$ will produce=$\frac{3}{2}\times 0.28=0.42moles$  of $SO_3$  

Mass of $SO_3=moles\times {\text {Molar mass}}=0.42moles\times 80g/mol=33.6g$

Thus theoretical yield of $SO_3$ produced by 8.96 g of S is 33.6 g