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Lesechka [4]
3 years ago
8

60m27Co → 6027Co Predict the type of radioactive emission produced from the decay of metastable cobalt-60 to cobalt-60. Describe

this type of emission and its reaction to an electric field. A) During the radioactive decay, alpha particles are released. These positive particles are attracted to the negative plate in the electric field and represent a ground energy level. B) Beta particles are released during the radioactive decay. These negative particles are attracted to the positive plate in the electric field and represent an excited energy state. C) Radioactive gamma decay is produced by the reaction. This neutral electromagnetic radiation allows the isotope to return to its ground state and is not attracted to the electric field. D) Both types of radioactive emissions, particles and electromagnetic radiation, are produced during this decay. None of these are attracted to the electric field and both present an intermediate level. Eliminate
Physics
1 answer:
lara [203]3 years ago
4 0
Some one already asked this question and you can copy paste and google it but I believe it is c you may want to double check
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A source emits sound with a frequency of 860 Hz. It is moving at 20.0 m/s toward a stationary reflecting wall. If the speed of s
Galina-37 [17]

Answer:

f_o=860\ Hz

Explanation:

Given:

  • original frequency of sound wave, f=860\ Hz
  • speed of the sound source, v_s=20\ m.s^{-1}
  • original speed of sound wave from the source, s=343\ m.s^{-1}

<u>According to the Doppler's effect:</u>

\frac{f_s}{f_o} =\frac{s+v_s}{s-v_o}

The sound is reflected from the wall and the source is moving towards the wall and observer is also riding the same source.

The velocity of the observer, v_o=-20\ m.s^{-1}

\frac{860}{f_o} =\frac{s+20}{s-(-20)}

f_o=860\ Hz

3 0
3 years ago
Read 2 more answers
The force of attraction between a positive ion and a negative ion in an ionic<br> compound
Crazy boy [7]
Force of attraction between one atom and another within a compound formed by sharing of electrons or the loss and gain of electrons this is a bond
3 0
3 years ago
Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.650 µC charge and flies due west at a speed of
Ganezh [65]

Answer : F=2808\times 10^{-11}\ N

Explanation :

It is given that,

Charge, q=0.650\ \mu C=0.65\times 10^{-6}\ C

Velocity of Aircraft, v=540\ m/s  (in west)

Magnetic field, B=8 \times 10^{-5}\ T ( in north )

Using the relation as :

F=q(v\times B)

Magnetic force is ,

F=0.65\times 10^{-6}\ C\times 540\ m/s\times 8 \times 10^{-5}\ T

F=2808\times 10^{-11}\ N

Using Right hand thumb rule, the direction of force is in the plane perpendicular to the velocity and the magnetic field i.e. -\hat{k}.

4 0
4 years ago
Which of the following has been identified as one of the seven basic emotions that are present as early as infancy?
Irina-Kira [14]

The answer is c. interest.

4 0
3 years ago
If this did not happen, what would be the approximate force on an eardrum of area 0.22 cm2 if a change in altitude of 1500 m tak
jeyben [28]

Complete Question

When you ascend or descend a great deal when driving in a car yours ears "pop," which means that the pressure behind the eardrum is being equalized to that outside. If this did not happen, what would be the approximate force on an eardrum of area .50 cm2 if a change in altitude of 950 m takes place?

Answer:

The value is F    = 0.60 \  N

Explanation:

From the question we are told that

   The area of the ear drum is  A = 0.5 \  cm^2 = 0.50 *10^{-4} \  m^2

    The change in altitude is  \Delta d  = 950 \  m

Generally the change in pressure is mathematically represented as

       \Delta P = \frac{F}{A}

This can also be mathematically represented as

      \Delta P = \rho * g *  \Delta d

So

       \frac{F}{A}     = \rho * g *  \Delta d

=>    F    = \rho * g *  \Delta d  *  A

=>    F    = \rho * g *  \Delta d  *  A

Here \rho is the density of dry air with value  \rho =  1.29 \ kg /m^3

So

     F    = 1.29 * 9.8 *  950  *  0.50 *10^{-4}

=> F    = 0.60 \  N

3 0
3 years ago
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