Displacement vectors of 4km north, 2km south, 5km north, 5km south combine to a total displacement of

Physics

1 answer:

goldfiish [28.3K]3 years ago

5 0

Answer

The combined displacement is 2km north

Explanation

Since displacement is a vector quantity, we take into account the direction.

Good for us all the displacement vectors are in the same dimension, so we can make north positive and south negative or vice-versa.

We now add to obtain,

$4+-2+5+-5$

This will simplify to

$=4-2+5-5=2$

Therefore the combined displacement is 2km north

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The following currents are measured in the same direction in a three-branch parallel circuit: 250 mA, 300 mA, and 800 mA. What i

Ksju [112]

The current in the junction is 1350 mA or 1.350 A.

Explanation:

As per Kirchoff's first law, the algebraic sum of current meeting at any junction should be equal to the algebraic sum of current leaving the junction. As in the present case, three parallel branch circuit is given the current in 250 mA, 300 mA and 800 mA, respectively, the sum of these three current will be equal to the current in the junction.

So,

I₁+I₂+I₃ = I₄

So I₁,I₂ and I₃ are the current passed in the three parallel branches and I₄ is the current in the junction.

250 + 300 + 800 = 1350 mA

So the current in the junction is 1350 mA or 1.350 A.

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Nataly [62]

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3 years ago

Draw a winding path that covers a distance of 70 miles and finishes with a displacement 20 miles soulthwest of the starting poin

EleoNora [17]

Distance is indeed a scalar amount that also refers to "how the ground an object has encased", and the Displacement is a vector thing that leads "to the extent to which an object is located", and the further calculation can be defined as follows:

Given:

distance= 70 miles

displacement = 20 miles