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enot [183]
3 years ago
15

A flat square plate of side 20cm moves over other similar plate with a thin layer of 0.4cm of a liquid between them with force 1

Kgw moves of the plates uniformly with a velocity 1m/s. Calculate co-efficient of viscosity of the liquid.
Physics
1 answer:
antiseptic1488 [7]3 years ago
7 0

Answer:

\mu=0.98\ Pa.s

Explanation:

Given:

  • dimension of square plate, l=0.2\ m
  • thickness of fluid layer, dy=0.004\ m
  • force on the fluid due to plate, F=1\ kgw=1\times 9.8=9.8\ N
  • velocity of plate, du=1\ m.s^{-1}

<u>Using Newton's law of viscosity:</u>

\tau=\mu.\frac{du}{dy} ..........................................(1)

where:

\tau= shear force on the surface on the fluid

\mu= coefficient of (dynamic) viscosity

Now, shear force:

\tau=\frac{shear\ force}{area}

\tau=\frac{9.8}{0.2\times0.2} \ Pa

Putting respective values in eq.(1)

\frac{9.8}{0.2\times0.2}=\mu\times\frac{1}{0.004}

\mu=0.98\ Pa.s

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