Answer:
Product: ethyl L-valinate
Explanation:
If we want to understand what it is the molecule produced we have to an<u>alyze the reagents</u>. We have valine an <u>amino acid</u>, in this kind of compounds we have an <em>amine group</em> (
) and a <em>carboxylic acid</em> group (
). Additionally, we have an <u>alcohol </u>(
) in the presence of HCl (a <u>strong acid</u>) in the first step, and a base (
).
When we have an acid and an alcohol in a vessel we will have an <u>esterification reaction</u>. In other words, an ester is produced. As the <em>first step,</em> the oxygen in the C=O (in the carboxylic acid group) would be protonated. In the <em>second step</em>, the ethanol attacks the carbon in the C=O of the carboxylic acid group producing a new bond between the oxygen in the ethanol and the carbon in the carboxylic acid. In <em>step 3</em>, a proton is transferred to produce a better leaving group (
). In <em>step 4</em>, a water molecule leaves the main structure to produce again the double bond C=O. <em>Finally</em>, a base (
) removes the hydrogen from the C=O bond to produce ethyl L-valinate
See figure 1
I hope it helps!
Answer:
3.74 M
Explanation:
We know that molarity is moles divided by liters. The first thing to do here is convert your 1500 mL of solution to L. There's 1,000 mL in 1 L, so you need to divide 1500 by 1000:
1500 ÷ 1000 = 1.50
Now you can plug your values into the equation for molarity:
5.60 mol ÷ 1.50 L = 3.74 M
The answer to this is yes they are likely, true.
1) Substances ( Solid<span>, Liquid, Gases ) which produce vapors will </span>burn<span> with </span>flame<span>. ... A yellow </span>flame<span> is produced during incomplete combustion of a substance. In Kerosene stove if yellow </span>flame<span> is observed then it indicates the incomplete combustion which may be due to the insufficient supply of oxygen gas. is it from researching so good luck :D </span>