1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitry_Shevchenko [17]
3 years ago
15

A tennis ball, a bowling ball, and a feather are dropped from the top of a tall building at the same time. Consider what you hav

e learned about air resistance. Which object reaches the ground first?

Physics
1 answer:
lord [1]3 years ago
7 0
The object that reaches the ground first is thebowling ball i think because it weighs heavier but when the tennis ball hits the ground it will bounce again and again till it stops and the bowling ball will just stop it wont bounce
You might be interested in
Water having a density of 1000 kg/m^3 is flowing with a velocity of 3 m/s through a round pipe. There is a restriction within th
Fofino [41]

Answer:

12 m/s

Explanation:

Using the continuity equation, which is an extension of the conservation of mass law

ρ₁A₁v₁ = ρ₂A₂v₂

where 1 and 2 indicate the conditions at two different points of flow, in this case, point 1 is any normal position in the pip and point 2 is the conditions at the restriction.

ρ = density of the fluid flowing; note that the density of the fluid flowing (water) is constant all through the fluid's flow

A₁ = Cross sectional Area of the pipe at point 1 = (πD₁²/4)

A₂ = Cross sectional Area of the pipe at the restriction = (πD₂²/4)

v₁ = velocity of the fluid flowing at point 1 = 3 m/s

v₂ = velocity of the fluid flowing at The restriction = ?

ρ₁A₁v₁ = ρ₂A₂v₂

Becomes

A₁v₁ = A₂v₂ (since ρ₁ = ρ₂)

(πD₁²/4) × 3 = (πD₂²/4) × v₂

3D₁² = D₂² × v₂

But

D₂ = (D₁/2)

And D₂² = (D₁²/4)

3D₁² = D₂² × v₂

3D₁² = (D₁²/4) × v₂

(D₁²/4) × v₂ = 3D₁²

v₂ = 4×3 = 12 m/s

8 0
3 years ago
A uniform solid sphere rolls down an incline. A) What must be the incline angle (deg) if the linear acceleration of the center o
Nonamiya [84]

Answer:

a) θ = 12.12°

b) equal to 0.21g

Explanation:

Solution:-

Declare variables:

- The mass of solid sphere, m

- The inclination angle, θ

- The linear acceleration a down the slope of the solid sphere is a = 0.21g

Where, g: The gravitational acceleration constant.

- The component of weight of solid sphere directed down the slope is given by:

                          Ws = m*g*sin ( θ )

- Apply Newton's second law of motion down the slope, state:

                        F_net = m*a

- The only net force acting on the solid sphere is the Weight. So, the equation of motion in the coordinate axis ( down the slope ).

                        Ws = m*a

                        m*g*sin ( θ ) = m*0.21*g

- Solve for inclination angle ( θ ):

                        sin ( θ ) = 0.21

                        θ = arcsin ( 0.21 )

                        θ = 12.12°

- If a friction-less block of mass ( m ) moves down the same slope then block has weight component down the slope as:

                         Wb = m*g*sin ( θ )

- Apply Newton's second law of motion down the slope, state:

                        F_net = m*a

- The only net force acting on the solid sphere is the Weight. So, the equation of motion in the coordinate axis ( down the slope ).

                        Ws = m*a

                        m*g*sin ( θ ) = m*a

- Solve for linear acceleration ( a ):

                        g*sin ( θ ) = a

                        a = sin ( 12.12 ) * g

                        a = 0.21g

Answer: The acceleration is independent of mass and only depends on the inclination angle θ.

7 0
4 years ago
How is artificial gravity created in spaceships and sattelites ?????? U need some IQ for this
goldfiish [28.3K]

Explanation:

Artificial gravity can be created using a centripetal force. A centripetal force directed towards the center of the turn is required for any object to move in a circular path. In the context of a rotating space station it is the normal force provided by the spacecraft's hull that acts as centripetal force.

Hope it helps.

4 0
3 years ago
Read 2 more answers
A boat crossing a 153.0 m wide river is directed so that it will cross the river as quickly as possible. The boat has a speed of
Lynna [10]

We have the relation

\vec v_{B \mid E} = \vec v_{B \mid R} + \vec v_{R \mid E}

where v_{A \mid B} denotes the velocity of a body A relative to another body B; here I use B for boat, E for Earth, and R for river.

We're given speeds

v_{B \mid R} = 5.10 \dfrac{\rm m}{\rm s}

v_{R \mid E} = 3.70 \dfrac{\rm m}{\rm s}

Let's assume the river flows South-to-North, so that

\vec v_{R \mid E} = v_{R \mid E} \, \vec\jmath

and let -90^\circ < \theta < 90^\circ be the angle made by the boat relative to East (i.e. -90° corresponds to due South, 0° to due East, and +90° to due North), so that

\vec v_{B \mid R} = v_{B \mid R} \left(\cos(\theta) \,\vec\imath + \sin(\theta) \, \vec\jmath\right)

Then the velocity of the boat relative to the Earth is

\vec v_{B\mid E} = v_{B \mid R} \cos(\theta) \, \vec\imath + \left(v_{B \mid R} \sin(\theta) + v_{R \mid E}\right) \,\vec\jmath

The crossing is 153.0 m wide, so that for some time t we have

153.0\,\mathrm m = v_{B\mid R} \cos(\theta) t \implies t = \dfrac{153.0\,\rm m}{\left(5.10\frac{\rm m}{\rm s}\right) \cos(\theta)} = 30.0 \sec(\theta) \, \mathrm s

which is minimized when \theta=0^\circ so the crossing takes the minimum 30.0 s when the boat is pointing due East.

It follows that

\vec v_{B \mid E} = v_{B \mid R} \,\vec\imath + \vec v_{R \mid E} \,\vec\jmath \\\\ \implies v_{B \mid E} = \sqrt{\left(5.10\dfrac{\rm m}{\rm s}\right)^2 + \left(3.70\dfrac{\rm m}{\rm s}\right)^2} \approx 6.30 \dfrac{\rm m}{\rm s}

The boat's position \vec x at time t is

\vec x = \vec v_{B\mid E} t

so that after 30.0 s, the boat's final position on the other side of the river is

\vec x(30.0\,\mathrm s) = (153\,\mathrm m) \,\vec\imath + (111\,\mathrm m)\,\vec\jmath

and the boat would have traveled a total distance of

\|\vec x(30.0\,\mathrm s)\| = \sqrt{(153\,\mathrm m)^2 + (111\,\mathrm m)^2} \approx \boxed{189\,\mathrm m}

3 0
2 years ago
Design a modified priority encoder that receives an 8-bit input, A7:0and produces a 3-bit output, Y2:0. Y indicates the most sig
cupoosta [38]

Answer:

Explanation:

The first image that I attached to this solution is the diagram of a truth table for an 8 to 3 bit encoder.

The second image  gives a sketch of the schematic.

The Boolean expression for the priority encoder including its zero inputs is defined in the third image attached.

Below is a snippet of the code for an 8 to 3 bit Priority encoder:

library IEEE;

use IEEE.STD_LOGIC_1164.all;

entity encoder8_3 is

   port(

       din : in STD_LOGIC_VECTOR(7 downto 0);

       dout : out STD_LOGIC_VECTOR(2 downto 0)

        );

end encoder8_3;

architecture encoder8_3_arc of encoder8_3 is

begin

   dout <= "000" when (din="10000000") else

           "001" when (din="01000000") else

           "010" when (din="00100000") else

           "011" when (din="00010000") else

           "100" when (din="00001000") else

           "101" when (din="00000100") else

           "110" when (din="00000010") else

           "111";

end encoder8_3_arc;

3 0
3 years ago
Other questions:
  • One student did an experiment on the rock cycle.
    15·1 answer
  • Water pressurized to 3 ´ 105 Pa is flowing at 5.0 m/s in a pipe which contracts to 1/3 of its former area. What are the pressure
    12·2 answers
  • When the sun warms the sidewalk on a hot sunny day, what type of energy conversion occurs?
    13·2 answers
  • What would happen to the seasons if the Earth’s tilt was only 10 degrees and why? What about 50 degrees and why?
    12·1 answer
  • *HELP ASAP* The Earth's___retains the atmosphere from dissipating into space.
    11·2 answers
  • “Why can I sometimes see the moon during the day?“Why can I sometimes see the moon during the day?
    10·1 answer
  • What is the Real anti virus software?
    15·2 answers
  • An airplane is flying at an elevation of 6 miles on a flight path that will take it directly over a radar tracking station. Let
    6·1 answer
  • An instrument that simply measures earth waves is a _______
    12·1 answer
  • If a force of 32000N exerted pressure of 160N/m² , find the area on which the force acts.​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!