9,000/12=750
Speed is equal to distance divided by time
Answer:
hi
Here are the answers you need
a. Romi's speed = slope of graph = 1000/15 - 0 = 66m/min
b. for 10 minute
c. I do not know the answer for this question, please forgive me
d.at 1000m from home they meet
I hope this helps you.
May god bless you and if you like this answer and think it helped you very much please mark me as brainliest because that will help me very much.
Answer:
No, the truck will not cross the barrier.
The closeness of the truck to the barrier is of 21.875 m
Solution:
As per the question:
Velocity of the truck, v = 25.0 m/s
Acceleration of the truck, a = - 4 
Now,
Since, the barrier at a distance of 100 m. Thus in order to check whether the truck hit the barrier or not, we will see the distance, d it covers by using the kinematic eqn:
Final velocity, v' = 0 m/s
Initial velocity = v
Now,
d = 78.125 m
Thus the truck will not cross the barrier.
Distance between the barrier and the truck:
100 - 78.125 = 21.875 m
From Newton's law v^2 = u^2 + 2as where a is the acceleration and s is the distance.
But to go any further, we need to know how fast the vehicle is accelerating
From v = u +at
We have a = u/t where the final velocity v = 0
So in one minute acceleration = (35 / 60) / 60 = 0.0097 ms/2. The first
experession in bracket is the initial velocity, u, in metres per seconds.
Hence v^2 = (0.583)^2 + 2 (0.0097)(30)
v^2 = 0.3398 + 0.5826 = 0.9224
v = âš 0.9224 = 0.960m
Answer:
V2 = 1.899*10^-3 m^3
T2 = 347.125 K
Explanation:
Using gas law, we know that
PV = nRT,
Where
V1 = 0.00115743 m^3.
gamma = 1.4
Now, when we solve for final volume, V2 we get
V2 = V1/((P2/P1)^(1/gamma))
V2 = 1.899*10^-3 m^3
Using the same law and method, when we try to solve for the temperature, we find that the final temperature, T2 is
T2 = T1*((V1/V2)^(gamma-1))
T2 = 347.125 K
