A ball rolls along a smooth horizontal floor at 10 m/s, then starts up a 20 degree ramp. How high does it go before rolling back
1 answer:
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Answer:
9.25
Explanation:
Let first find the moles of and
number of moles of = 0.40 mol/L × 200 × 10⁻³L
= 0.08 mole
number of moles of = 0.80 mol/L × 50 × 10⁻³L
= 0.04 mole
The equation for the reaction is expressed as:
The ICE Table is shown below as follows:
Initial (M) 0.08 0.04 0
Change (M) - 0.04 -0.04 + 0.04
Equilibrium (M) 0.04 0 0.04
for buffer solutions
since they are in the same solution
Answer:
57.48%
Explanation:
Calculate the mass of 1 mole of malachite:
MM Cu = 63.55
MM O = 16.00
MM H = 1.01
MM C = 12.01
A mole of malachite has:
2 moles of Cu
5 moles of O
2 moles of H
1 mole of C
MW Malachite = 2*MM(CU) + 5*MM(O) + 2*MM(H) + 1 *MM(C)
MW Malachite = 2*63.55 + 5*16.00 + 2*1.01 + 1*12.01
MW Malachite = 221.13
Mass of Cu in a mole of Malachite = 2*MM(CU) = 127.1
Now divide the mass of Cu by the mass of Malachite