What is the physical state of a straight-chain hydrocarbon containing three carbon atoms at room temperature?

Chemistry

2 answers:

WARRIOR [948]3 years ago

8 0

Answer: Gaseous

Explanation: Straight Chain hydrocarbon having three carbon atoms is known as Propane. It molecular formula is

CH_{3}CH_{2}CH_{3}

Inter molecular forces of attraction that is London Dispersion Forces existing between its molecules are weaker that is why the propane is gaseous in nature at room temperature.

It is also used in LPG. Boiling Point of propane is -42° C.

madam [21]3 years ago

6 0

The straight-chain hydrocarbon containing three carbon atoms is propane. It's molecular formula is C3H8.

Following is the structure of propane
CH3-CH2-CH3

Boiling point of propane is -42 oC, this suggest that propane is gas at room temperature.

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How many grams of O2 are present in 44.1 L of O2 at STP?

ycow [4]

Taking into accoun the STP conditions and the ideal gas law, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.

First of all, the STP conditions refer to the standard temperature and pressure, where the values used are: pressure at 1 atmosphere and temperature at 0°C. These values are reference values for gases.

On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

P is the gas pressure.
V is the volume that occupies.
T is its temperature.
R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
n is the number of moles of the gas.

Then, in this case:

P= 1 atm
V= 44.1 L
n= ?
R= 0.082 $\frac{atmL}{molK}$
T= 0°C =273 K

Replacing in the expression for the ideal gas law:

1 atm× 44.1 L= n× 0.082 $\frac{atmL}{molK}$ × 273 K

Solving:

$n=\frac{1 atm x44.1 L}{0.082\frac{atmL}{molK}x273K}$

n=1.97 moles

Being the molar mass of O₂, that is, the mass of one mole of the compound, 32 g/mole, the amount of mass that 1.97 moles contains can be calculated as:

$1.97 molesx\frac{32 g}{1 mole}$ = 63.04 g ≈ 63 g