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Archy [21]
3 years ago
10

Cyclopropane is converted to propene in a first–order process with a rate constant of 5.4 × 10–2 hour–1 . The initial concentrat

ion of cyclopropane is 0.150 M. Estimate the concentration of cyclopropane after 22.0 hours
Chemistry
1 answer:
Hitman42 [59]3 years ago
3 0

Answer:

The concentration of cyclopropane after 22.0 hour is 0.0457 M.

Explanation:

Conversion of cyclopropane into propene follows first order kinetics.

The integrated rate of first order kinetic is given by :

[A]=[A_o]\times e^{-kt}

[A_o] = Initial concentration of reactant

[A] = final concentration of reactant after time t

k = rate constant of the reaction

We have :

Rate constant of the reaction = k = 5.4\times 10^{-2} hour^{-1}

[A_o]=0.150 M

t = 22.0 hour

[A] =?

[A]=0.150 M\times e^{-5.4\times 10^{-2} hour^{-1}\times 22.hour}

[A]=0.0457 M

The concentration of cyclopropane after 22.0 hour is 0.0457 M.

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snow_tiger [21]

Answer:

T_2=261.46\ K

Explanation:

It is given that,

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According to Charles law, at constant pressure, V\propto T

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3 years ago
50.0 mL of 0.200 M HNO2 is titrated to its equivalence point with 1.00 M NaOH. What is the pH at the equivalence point?
yKpoI14uk [10]

Answer:

8.279

Explanation:

The pH can be determined by hydrolysis of a conjugate base of weak acid at the equivalence point.

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           = 5.00 m-mol

           = 0.005 mol

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Now the ICE table :

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I (M)       0.167                   0            0

C (M)         -x                      +x          +x

E (M)      0.167-x                  x           x

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$K_w=K_a \times K_b$            $(K_w \text{ is the ionic product of water })$

$K_b =\frac{K_w}{K_a}$

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Now, since pH + pOH = 14

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                = 8.279

Therefore the ph is 8.279 at the end of the titration.

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