We can solve the equation and show the solution below:
Oxygen atomic number is 16.
Phosphorus atomic number is 32.
We have the molecular weight:
Molecular weight = (31*4) + (16*10)
Molecular weight = 284 grams/mol
Solving for the grams:
0.4 mole (for P4) * (1 mol P4O10/1 mol P4) * (284 grams P4O10/1 mole P4O10)
Total grams = 113.6
The answer is 113.6 grams.
Darwin observed the beaks of the birds and how the different beaks helped the birds to eat different types of seeds.
This relates to natural selection because certain finches with say a smaller shorter beak would be able to eat only smaller seeds and fruits as to where a finch with a longer larger beak could eat larger bigger seeds and fruits.
Hope this helped! Have a great day!
Answer:
yes it is true
Explanation:
evaporation occurs when burning liquid water changes into gas.
Answer:
Mass of hydrogen produced =2.28 g
Explanation:
Given data:
Mass of tin = 67.3 g
Mass of hydrogen produced = ?
Solution:
Chemical equation:
Sn + 2H₂O → SnO₂+ 2H₂
Number of moles of Sn:
Number of moles = mass/ molar mass
Number of moles = 67.3 g/ 118.71 g/mol
Number of moles = 0.57 mol
Now we will compare the moles of tin with hydrogen from balance chemical equation.
Sn : H₂
1 : 2
0.57 : 2×0.57 = 1.14
Mass of hydrogen:
Mass = number of moles ×molar mass
Mass = 1.14 mol × 2 g/mol
Mass = 2.28 g
Answer:
The concentration of fructose-6-phosphate F6P ≅ 1.35 mM
Explanation:
Given that:
ΔG°′ is the conversion of glucose-6-phosphate to fructose-6-phosphate (F6P) = +1.67 kJ/mol = 1670 J/mol
concentration of glucose-6-phosphate at equilibrium = 2.65 mM
Assuming temperature = 25.0°C
=( 25 + 273)K
= 298 K
We are to find the concentration of fructose-6-phosphate
Using the relation;
ΔG' = -RT In K_c
where;
R = 8.314 J/K/mol
1670 = - (8.314 × 298 ) In K_c
1670 = -2477.572 × In K_c
1670/ 2477.572 = In K_c
0.67 = In K_c
0.511
Now using the equilibrium constant 
![K_c = \dfrac{[F6P]}{[G6P]}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cdfrac%7B%5BF6P%5D%7D%7B%5BG6P%5D%7D)
![0.511 = \dfrac{[F6P]}{[2.65]}](https://tex.z-dn.net/?f=0.511%20%3D%20%20%5Cdfrac%7B%5BF6P%5D%7D%7B%5B2.65%5D%7D)
F6P = 0.511 × 2.65
F6P = 1.35415
F6P ≅ 1.35 mM
