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Yuki888 [10]
3 years ago
14

Which liquid is the most viscous? syrup water milk apple juice

Physics
2 answers:
Arlecino [84]3 years ago
8 0
Syrup is the most viscous out of the choices above  
Elza [17]3 years ago
4 0
The answer should be syrup
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Which of these samples of water has the most internal energy?
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Answer:

1kg steam will have the maximum energy

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Hey, guys I kinda need help with this question, 1. The number of atoms of each element are not equal on both sides of the equati
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The same number of atoms of each element must appear on both sides of a chemical equation. However, simply writing down the chemical formulas of reactants and products does not always result in equal numbers of atoms. You have to balance the equation to make the number of atoms equal on each side of an equation.

Explanation:

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3 years ago
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Two forces a 60 newton force east and an 80 newton force north
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Its resultant is 100 newton
√(60 square+80 square)
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3 years ago
A 200N force pushes forward on the 20kg truck. The truck pulls two crates connected together by ropes, as shown. The gravitation
devlian [24]

Force on left crate, right crate and truck we need to draw here

First we will write the equation for left crate

T_{left} = m*a

T_{left} = 20*a

Now similarly for right crate

T_{right} - T_{left} = 20*a

now for truck

F - T_{right} = 20*a

Now we know that F = 200 N

200 - T_{right} = 20*a

now add all three equation

T_{left} + T_{right} - T_{left} + 200 - T{right} = 20a + 20 a + 20a

200 = 60 a

a = 10/3 m/s^2

now we will find all tension using this value of acceleration

T_{left} = 20 * \frac{10}{3} = \frac{200}{3} N

T_{right} - \frac{200}{3} = 20*\frac{10}{3}

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6 0
3 years ago
How do I go about this?
Anna71 [15]

Hi there!

(a)

Recall that:
W = F \cdot d = Fdcos\theta

W = Work (J)
F = Force (N)
d = Displacement (m)

Since this is a dot product, we only use the component of force that is IN the direction of the displacement. We can use the horizontal component of the given force to solve for the work.

W =248(56)cos(30) = 12027.36 J

To the nearest multiple of ten:
W_A = \boxed{12030 J}

(b)
The object is not being displaced vertically. Since the displacement (horizontal) is perpendicular to the force of gravity (vertical), cos(90°) = 0, and there is NO work done by gravity.

Thus:
\boxed{W_g = 0 J}

(c)
Similarly, the normal force is perpendicular to the displacement, so:
\boxed{W_N = 0 J}

(d)

Recall that the force of kinetic friction is given by:
F_{f} =\mu_k mg

Since the force of friction resists the applied force (assigned the positive direction), the work due to friction is NEGATIVE because energy is being LOST. Thus:
W_f = -\mu_k mgd\\W_f = - (0.1)(56)(9.8)(56) = -3073.28 J

In multiples of ten:
\boxed{W_f = -3070 J}

(e)
Simply add up the above values of work to find the net work.

W_{net} = W_A + W_f \\\\W_{net} = 12027.36 + (-3073.28) = 8954.08 J

Nearest multiple of ten:
\boxed{W_{net} = 8950 J}}

(f)
Similarly, we can use a summation of forces in the HORIZONTAL direction. (cosine of the applied force)
F_{net} = F_{Ax} - F_f

W = F_{net} \cdot d = (F_{Ax} - F_f)

W = (F_Acos(30) - \mu_k mg)d\\W = (248cos(30) - 0.1(56)(9.8)) * 56 \\\\W = 8954.08 J

Nearest multiple of ten:
\boxed{W_{net} = 8950 J}

5 0
2 years ago
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