We know, a = (v₂-v₁) / (t₂-t₁)
Here, v₂-v₁ = 19 m/s
t₂-t₁ = 2 s
Substitute it into expression,
a = 19/2
a = 9.5 m/s²
So, your final answer is 9.5 m/s²
Hope this helps!
Answer:
the acceleration due to gravity, g of the cylinder is 9.81m/s2
Explanation:
since the cylinder is rolling down from a hill, the acceleration due to gravity of any object coming down from the atmosphere is always constant which is g=9.8m/s2 or approximately 10m/s2
