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3 years ago

The total amount of energy in a closed system stays the same. t/f

Physics

1 answer:

zvonat [6]3 years ago

5 0

True. Law of Conservation of energy

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Which of the following is a chemical change?

suter [353]

Answer:

B:melting of a cube of ice

Explanation:

because it comes out as ice then it melts into liquids

4 0

2 years ago

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A cable with mass 0.5 kilograms per meter (kg/m) is used to lift 150 kg of coal up a mine shaft 50 meters deep. Set up the integ

zalisa [80]

Answer:

$W=-\int_{0}^{50}[150-0.5y]dy$

Explanation:

the integral for the work is:

$W=\int\vec{F}\cdot d\vec{l}=\int(-M(y)g)dy$

the work is against the gravitational force. While the coal is going up, M(y) is changing due to the length of the cable is lower. We can describe this by using the following formula

$M(y)=150kg-0.5\frac{kg}{m}y$

Thus , the integral for the work is:

$W=-\int_{0}^{50}[150-0.5y]dy$

hope this helps!!

6 0

3 years ago

The full range of frequencies of electromagnetic radiation is called

Flura [38]

The correct answer is Electromagnetic spectrum, A,B and D are components of electromagnetic spectrum.

6 0

3 years ago

Read 2 more answers

A particle is confined to a one-dimensional box that is 50 pm long. What is the smallest possible uncertainty in momentum for th

nevsk [136]

Answer:

The smallest possibility is 0.01E-22kgm/s

Explanation:

Using

Momentum= h/4πx

= 6.6x 10^-34Js/ 4(3.142* 50*10-12m)

= 0.01*10^-22kgm/s

6 0

3 years ago

How to find a planet’s gravitational field strength using its radius?

grin007 [14]

The gravitational field strength is approximately equal to 10 N.

<u>Explanation:</u>

Gravitational field strength is the measure of gravitational force acting on any object placed on the surface of the planet. Generally, the mass of the object is considered as 1 kg.

So the gravitational field strength will be equal to the gravitational force acting on the object.

The formula for gravitational field strength is

$g = \frac{F}{m}$

Here g is the gravitational field strength, m is the mass of the object placed on the surface and F is the gravitational force acting on the object.

Since, the mass of any object placed on the surface of earth will be negligible compared to the mass of Earth, so the mass of the object is considered as 1 kg.

Then the g = F

And $F =\frac{GMm}{r^{2} }$

Here G is the gravitational constant, M is the mass of Earth and m is the mass of the object placed on the surface, while r is the radius of the Earth.

$g = F = \frac{6 \times 10^{24} \times 6.67 \times 10^{-11} \times 1}{(6.6 \times 10^{6}) ^{2} }$

$g = 0.977 \times 10^1= 9.77\ N$

So, the gravitational field strength is approximately equal to 10 N.

5 0

3 years ago