Question

A total of 620 C of charge passes through a flashlight in 0.510 h. What is the average current in milliamperes?

Answer 1

Explanation:

The given data is as follows.

               Q = 620 C,         t = 0.510 hour

First, we will convert hours into seconds. Since, there are 3600 seconds present in 1 hour. Hence, number of seconds present in 0.510 hour are as follows.

                   $0.510 hr \times \frac{3600 sec}{1 hr}$

                     = 1836 sec

Therefore, we will calculate the average current as follows.

                      I = $\frac{Q}{t}$

                        = $\frac{620 C}{1836 sec}$

                        = 0.337 C/sec

It is known that,

                      1 C/sec = 1000 mA

So,             $0.337 C/sec \times \frac{1000 mA}{1 C/s}$

                    = 337 mA

Thus, we can conclude that the average current in milliamperes is 337 mA.