If Shirley pushes one end of a desk to the right with a force of 12.0N and anfernee pushes the desk at the same time to the left
with a force of 19.0N and the desk has a mass of 4.50kg. What is the net force on the desk?
1 answer:
The net force does not depend on the mass.
We have 12N to the right, and 19N to the left.
The net force is (19.0-12.0)N=7.0N to the left.
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given,
mass of block (m)= 6.4 Kg
spring is stretched to distance, x = 0.28 m
initial velocity = 5.1 m/s
a) computing weight of spring
k x = m g
![k = \dfrac{mg}{x}](https://tex.z-dn.net/?f=k%20%3D%20%5Cdfrac%7Bmg%7D%7Bx%7D)
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b) ![f = \dfrac{\omega}{2\pi}](https://tex.z-dn.net/?f=f%20%3D%20%5Cdfrac%7B%5Comega%7D%7B2%5Cpi%7D)
![\omega = \sqrt{\dfrac{k}{m}}= \sqrt{\dfrac{224}{6.4}} = 5.92 \ rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Csqrt%7B%5Cdfrac%7Bk%7D%7Bm%7D%7D%3D%20%5Csqrt%7B%5Cdfrac%7B224%7D%7B6.4%7D%7D%20%3D%205.92%20%5C%20rad%2Fs)
![f = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}](https://tex.z-dn.net/?f=f%20%3D%20%5Cdfrac%7B1%7D%7B2%5Cpi%7D%5Csqrt%7B%5Cdfrac%7Bk%7D%7Bm%7D%7D)
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![v_b = -5.1 \times cos (5.92 \times 0.42)](https://tex.z-dn.net/?f=v_b%20%3D%20-5.1%20%5Ctimes%20cos%20%285.92%20%5Ctimes%200.42%29)
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=![6.4 \times 5.92^2\times 0.42](https://tex.z-dn.net/?f=6.4%20%5Ctimes%205.92%5E2%5Ctimes%200.42)
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