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satela [25.4K]
4 years ago
10

Velocity is a vector quantity which has both magnitude and direction. ... Net force is also a vector quantity which has both mag

nitude and direction. Using complete sentences, describe the net force acting upon the object during the course of the elliptical orbit. Comment on both the magnitude and the direction.
Physics
2 answers:
GuDViN [60]4 years ago
7 0
When the object is moving in the elliptical orbit, it means that the direction of its acceleration should be towards the two foci (plural of focus) of the ellipse to keep the elliptical motion. As force according to the Newton's second law: F = ma, the net force must be in the direction of the acceleration. As far as the magnitude of net force is concerned, you can use Newton's gravitational law to find its magnitude.
Lera25 [3.4K]4 years ago
3 0

The net force on an object moving in an elliptical path is the gravitational force. The force vector always points towards the object being orbited by the object following the elliptical orbit. In the case of the sun and earth, the force vector will always point towards the sun

The exact magnitude of the force is given by Newton's law of universal gravitation. The formula to calculate the magnitude of this force is ,F=\frac{GMm}{r^2}.

In this formula G is the universal gravitational constant, r is the distance between the two objects, M,m each represent the masses of the central object and the object orbiting it.  As a consequence we can tell that closer to the central object, the magnitude of the force will be larger than further away from the object.

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3 years ago
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A diamond is underwater; A light ray enters one face of the diamond, then travels at an angle of 30 degrees with respect to the
otez555 [7]
According to snells law 

<span>n1 sin theta1 = n2 sin theta2
</span>n1  = 1.333 (water)
<span>n2  = 2.42 (diamond)</span>
 it is given that theta =30 degrees so 
by putting the values we have 

<span>1.333 sin theta = 2.42 sin 30 </span>

<span>sin theta = (2.42/1.333) *0.5 =65.2 degree
</span>so our conclusion is 

<span>the ray's angle of incidence θ1 on the diamond</span> = 65.2 degree.
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4 0
4 years ago
A 10n force is applied to a 25kg mass to slide it across a frictional surface. What is the acceleration of the mass?
klasskru [66]

Answer: a = 0.4m/s^2 - 9.8*c where c is the coefficient of kinetic friction of the surface

Explanation: We know that, by the second Newton's law, a = F/m

where a is the acceleration, F is the net force and m is the mass of the object.

Then, if the surface is frictionless, the total force applied in the object is 10N, and the mass of the object is 25kg, so the acceleration is:

a =10N/25kg = 0.4m/s^2.

But if the surface is frictional, there will be a force of friction applied in the mass (this depends on the coefficient of friction and the weight of the mass), this means that the acceleration will be reduced.

If = -(9.8*25)*c

where c is a number that is bigger than 0 and smaller than 1, is called the coefficient of kinetic friction.

So the total force is now:

F = (10 - 9.8*25*c)

Then, the acceleration in a frictional surface is equal to:

a = (10 - 9.8*25*c)/25 = 0.4m/s^2 - 9.8*c

6 0
4 years ago
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5. The wire in consists of two segments of different diameters but made from the same metal. The current in segment 1 is I1. a.
Volgvan

Answer:

hello your question is incomplete attached below is the complete question

answer :

a) I1 = I2

b) J1 > J2

c) E 1 > E2

d) ( vd1 ) > ( vd2 )

Explanation:

a) The currents in the two segments are the same  i.e. I1 = I2  and this is because the segments are connected in series

b) Comparing the current densities J1 and J2 in the two segments

note : current density ∝ 1 / area

The area of the second segment is > the area of first segment  therefore

J1 > J2

J1 ( current density of first segment )

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c) Comparing the electric field strengths E1 and E2

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E 1 > E2

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drek231 [11]
For every actions, there is an opposite reaction.

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