Answer:
A) It contains a lot of matter.
Answer:
The equilibrium concentration of
.
The equilibrium concentration of
.
The equilibrium concentration of
.
Explanation:
Answer:
The equilibrium concentration of HCl is 0.01707 M.
Explanation:
Equilibrium constant of the reaction = 
Moles of 
Concentration of ![[PCl_3]=\frac{0.280 mol}{1.00 L}=0.280 M](https://tex.z-dn.net/?f=%5BPCl_3%5D%3D%5Cfrac%7B0.280%20mol%7D%7B1.00%20L%7D%3D0.280%20M)
Moles of 
Concentration of ![[Cl_2]=\frac{0.280 mol}{1.00 L}=0.280M](https://tex.z-dn.net/?f=%5BCl_2%5D%3D%5Cfrac%7B0.280%20mol%7D%7B1.00%20L%7D%3D0.280M)

Initial: 0.280 0.280 0
At eq'm: (0.280-x) (0.280-x) x
We are given:
![[PCl_3]_{eq}=(0.280-x)](https://tex.z-dn.net/?f=%5BPCl_3%5D_%7Beq%7D%3D%280.280-x%29)
![[Cl_2]_{eq}=(0.280-x)](https://tex.z-dn.net/?f=%5BCl_2%5D_%7Beq%7D%3D%280.280-x%29)
![[PCl_5]_{eq}=x](https://tex.z-dn.net/?f=%5BPCl_5%5D_%7Beq%7D%3Dx)
Calculating for 'x'. we get:
The expression of
for above reaction follows:
![K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BPCl_5%5D%7D%7B%5BPCl_3%5D%5BCl_2%5D%7D)
Putting values in above equation, we get:

On solving this quadratic equation we get:
x = 0.228, 0.344
0.228 M < 0.280 M< 0.344 M
x = 0.228 M
The equilibrium concentration of
.
The equilibrium concentration of
.
The equilibrium concentration of
.
Explanation :
In thermodynamics, a system is region or part of space which is being studied and observed while the surrounding is the region or space around the system which interacts with the system.
Here in the experiment ,system which is observed is reaction or changes when citric acid and sodium bicarbonate are mixed together. And the mixing is carried out in the calorimeter which serves as a surrounding around the system.
The reason behind the using the calorimeter is measure the energy change occurring during the reaction.
Answer:
A. ![K=\frac{[N_2O]^2}{[N_2]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BN_2O%5D%5E2%7D%7B%5BN_2%5D%5E2%5BO_2%5D%7D)
Explanation:
Hello there!
In this case, for us to figure out the appropriate equilibrium expression, it will be firstly necessary for us to recall the law of conservation of mass which states that the equilibrium constant of an equilibrium chemical reaction is written by dividing the products and reactants and including the stoichiometric coefficients as exponents. In such a way, for the given reaction, we will have:
![K=\frac{[N_2O]^2}{[N_2]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BN_2O%5D%5E2%7D%7B%5BN_2%5D%5E2%5BO_2%5D%7D)
As N2O is the product whereas N2 and O2 are reactants; thus, the equilibrium expression will be A.
Regards!