Answer: The volume of 0.640 grams of
gas at Standard Temperature and Pressure (STP) is 0.449 L.
Explanation:
Given: Mass of
gas = 0.640 g
Pressure = 1.0 atm
Temperature = 273 K
As number of moles is the mass of substance divided by its molar mass.
So, moles of
(molar mass = 32.0 g/mol) is as follows.

Now, ideal gas equation is used to calculate the volume as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.

Thus, we can conclude that the volume of 0.640 grams of
gas at Standard Temperature and Pressure (STP) is 0.449 L.
Answer:
5 valence electrons
Nitrogen has a total of 5 valence electrons
Explanation:
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Answer:
Approximately
, assuming that this acid is monoprotic.
Explanation:
Assume that this acid is monoprotic. Let
denote this acid.
.
Initial concentration of
without any dissociation:
.
After
of that was dissociated, the concentration of both
and
(conjugate base of this acid) would become:
.
Concentration of
in the solution after dissociation:
.
Let
,
, and
denote the concentration (in
or
) of the corresponding species at equilibrium. Calculate the acid dissociation constant
for
, under the assumption that this acid is monoprotic:
.