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Umnica [9.8K]
3 years ago
6

Echnician a says that to prevent injuries in an auto accident, all steering columns have a break-off steering wheel. technician

b says that to prevent injuries in an accident, all steering columns are now fitted with a flexible rubber tube. who is correct? choose one answer.
Physics
1 answer:
Oliga [24]3 years ago
4 0
<span>Technician a says that to prevent injuries in an auto accident, all steering columns have a break-off steering wheel. technician b says that to prevent injuries in an accident, all steering columns are now fitted with a flexible rubber tube. Both technicians are correct.   The </span>vehicle manufacturers use break away steering column mounting brackets to protect the driver in an accident.  The <span>vehicle manufacturers are required to use collapsible shafts in the steering column. </span>
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Virtual image formed by concave mirror<br>​
Elis [28]

Answer:

yes

Explanation:

because it is a diverging mirror

3 0
3 years ago
Two books are located 1 m above the surface of the Earth. The first has a mass of 2 kg; the second has a mass of 1 kg. Which sta
stepladder [879]
B, the acceleration due to gravity is 9.8m/s/s regardless of mass

3 0
3 years ago
A 6.00-m long string sustains a three-loop standing wave pattern as shown. The wave speed is 2.00 × 102 m/s.What is the lowest p
KATRIN_1 [288]

Given:

The length of the string is l = 6 m

The speed of the wave is

v=2\times10^2\text{ m/s}

Required: Lowest possible frequency for the standing wave.

Explanation:

The lowest possible frequency is the fundamental frequency.

The fundamental frequency can be calculated by the formula

f=\frac{v}{2l}

On substituting the values, the fundamental frequency will be

\begin{gathered} f=\frac{2\times10^2}{2\times6} \\ =16.67\text{ Hz} \end{gathered}

Final Answer: The lowest possible frequency for standing waves on this string is 16.67 Hz

4 0
2 years ago
A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a sound with
Ymorist [56]

Answer:

the frequency of the beats is 8.7687 kHz

Explanation:  

Given the data in the question;

The frequency for stationary source and moving observer is;

f' = f( 1 +( v_observer/v_sound))

we know that, speed of sound in dry air =  343 m/s

so we substitute

f' = 41.2 kHz( 1 + (33.0 m/s / 343 m/s) ) = 41.2kHz( 1 + 0.0962) = 41.2kHz(1.0962)

f' = 45.1634 kHz

Now the frequency for stationary observer and moving source with frequency f' will be

f" = f'( 1 / (1 - ( v_observer/v_sound)))

45.1634 kHz( 343 / 343 - 33)

we substitute

f" = 45.1634 kHz( 1 / (1 - (33.0 m/s / 343 m/s)))

f" = 45.1634 kHz( 1 / (1 - 0.0962))

f" = 45.1634 kHz( 1 / 0.9038 )

f" = 45.1634 kHz( 1.1064 )

f" = 49.9687 kHz

Now the beat frequency will be;

f_beat = f' - f

we substitute

f_beat = 49.9687 kHz - 41.2 kHz

f_beat = 8.7687 kHz

Therefore, the frequency of the beats is 8.7687 kHz

7 0
3 years ago
A powerful missile reaches a speed of 5 kilometers per second in 10 seconds after its launch. What is the average acceleration o
bixtya [17]

Answer:

D

Explanation:

5 Km=5000m

so Δv=5000 m/sec

a=Δv/Δt

=5000/10

a=500 m/sec²                 as 500÷1000=0.5 Km

a=0.5 km/sec²

so D is the right answer.

3 0
3 years ago
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