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kvasek [131]
2 years ago
7

The "Big Dig" was the nickname of the civil engineering project that redesigned the highway Infrastructure for the city of

Engineering
1 answer:
zheka24 [161]2 years ago
4 0
Geotechnical since it’s geologicaly based
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Air exits a compressor operating at steady-state, steady-flow conditions at 150 oC, 825 kPa, with a velocity of 10 m/s through a
ioda

Answer:

a) Qe = 0.01963 m^3 / s , mass flow rate m^ = 0.1334 kg/s

b) Inlet cross sectional area = Ai = 0.11217 m^2 , Qi = 0.11217 m^3 / s    

Explanation:

Given:-

- The compressor exit conditions are given as follows:

                  Pressure ( Pe ) = 825 KPa

                  Temperature ( Te ) = 150°C

                  Velocity ( Ve ) = 10 m/s

                  Diameter ( de ) = 5.0 cm

Solution:-

- Define inlet parameters:

                  Pressure = Pi = 100 KPa

                  Temperature = Ti = 20.0

                  Velocity = Vi = 1.0 m/s

                  Area = Ai

- From definition the volumetric flow rate at outlet ( Qe ) is determined by the following equation:

                   Qe = Ae*Ve

Where,

           Ae: The exit cross sectional area

                   Ae = π*de^2 / 4

Therefore,

                  Qe = Ve*π*de^2 / 4

                  Qe = 10*π*0.05^2 / 4

                  Qe = 0.01963 m^3 / s

 

- To determine the mass flow rate ( m^ ) through the compressor we need to determine the density of air at exit using exit conditions.

- We will assume air to be an ideal gas. Thus using the ideal gas state equation we have:

                   Pe / ρe = R*Te  

Where,

           Te: The absolute temperature at exit

           ρe: The density of air at exit

           R: the specific gas constant for air = 0.287 KJ /kg.K

             

                ρe = Pe / (R*Te)

                ρe = 825 / (0.287*( 273 + 150 ) )

                ρe = 6.79566 kg/m^3

- The mass flow rate ( m^ ) is given:

               m^ = ρe*Qe

                     = ( 6.79566 )*( 0.01963 )

                     = 0.1334 kg/s

- We will use the "continuity equation " for steady state flow inside the compressor i.e mass flow rate remains constant:

              m^ = ρe*Ae*Ve = ρi*Ai*Vi

- Density of air at inlet using inlet conditions. Again, using the ideal gas state equation:

               Pi / ρi = R*Ti  

Where,

           Ti: The absolute temperature at inlet

           ρi: The density of air at inlet

           R: the specific gas constant for air = 0.287 KJ /kg.K

             

                ρi = Pi / (R*Ti)

                ρi = 100 / (0.287*( 273 + 20 ) )

                ρi = 1.18918 kg/m^3

Using continuity expression:

               Ai = m^ / ρi*Vi

               Ai = 0.1334 / 1.18918*1

               Ai = 0.11217 m^2          

- From definition the volumetric flow rate at inlet ( Qi ) is determined by the following equation:

                   Qi = Ai*Vi

Where,

           Ai: The inlet cross sectional area

                  Qi = 0.11217*1

                  Qi = 0.11217 m^3 / s    

- The equations that will help us with required plots are:

Inlet cross section area ( Ai )

                Ai = m^ / ρi*Vi  

                Ai = 0.1334 / 1.18918*Vi

                Ai ( V ) = 0.11217 / Vi   .... Eq 1

Inlet flow rate ( Qi ):

                Qi = 0.11217 m^3 / s ... constant  Eq 2

               

6 0
3 years ago
Sensors are used to monitor the pressure and the temperature of a chemical solution stored in a vat. The circuitry for each sens
JulsSmile [24]
Circle because it’s round and we all love round things
5 0
3 years ago
Your family has asked you to estimate the operating costs of your clothes dryer for the year. The clothes dryer in your home has
trasher [3.6K]

Answer:

The costs to run the dryer for one year are $ 9.03.

Explanation:

Given that the clothes dryer in my home has a power rating of 2250 Watts, and to dry one typical load of clothes the dryer will run for approximately 45 minutes, and in Ontario, the cost of electricity is $ 0.11 / kWh, to calculate the costs to run the dryer for one year the following calculation must be performed:

1 watt = 0.001 kilowatt

2250/45 = 50 watts per minute

45 x 365 = 16,425 / 60 = 273.75 hours of consumption

50 x 60 = 300 watt = 0.3 kw / h

0.3 x 273.75 = 82.125

82.125 x 0.11 = 9.03

Therefore, the costs to run the dryer for one year are $ 9.03.

8 0
2 years ago
Write down at least two things that the mine winch
sveticcg [70]
I don’t know what the
4 0
3 years ago
The pressure rise Ap associated with wind hitting a win- dow of a building can be estimated using the formula Ap-p(12/2), where
Harrizon [31]

Answer:

a. 430.944 pascal

b. 0.0625psi

c. 1.73008inH20

Explanation:

The pressure rise Ap associated with wind hitting a win- dow of a building can be estimated using the formula Ap-p(12/2), where p is density of air and V is the speed of the wind. Apply the grid method to calculate pressure rise for P-1.2 kg/m and V-60 mph. a. Express your answer in pascals. b. Express your answer in pounds-force per square inch (psi). c. Express your answer in inches of water column

checking the dimensional consistency

Dp=\frac{kg}{m^3} (\frac{m^2}{s^2} \\\frac{x}{y} \\\\\frac{kg}{ms^2} \\which s the same as\\ \frac{N}{m^2}

Dp=∈(\frac{v^2}{2} )

convert 1 mile to meter

1mile=1609m

1h=3600s

60mile/h=26.8m/s

slotting intpo the relation

Dp=1.2kg/m^3(\frac{26.8^2}{2} )

430.944kg/(ms^2)

which is the same as 430.944N/m^2

expressing in pascal.

We know that

1 pascal=1 N/m^2

430.944 pascal

2. 1 pascal=0.000145psi

answer=0.0625psi

3.1 pascal=0.00401inH20

answer=430.944*0.0040146

1.73008inH20

5 0
3 years ago
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