Answer:
80 feet
Step-by-step explanation:
Given:
Initial speed of the car () = 40 ft/sec
Deceleration of the car () = -10 ft/sec²
Final speed of the car () = 0 ft/sec
Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.
Now, deceleration means rate of decrease of velocity.
So,
Negative sign means the velocity is decreasing with time.
Now, using chain rule of differentiation. Therefore,
Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,
Therefore, the car travels a distance of 80 feet before stopping.