Answer:
"A turbine takes the kinetic energy of a moving fluid, air in this case, and converts it to a rotary motion. As wind moves past the blades of a wind turbine, it moves or rotates the blades. These blades turn a generator."
Answer:
1. 0.574 kJ/kg
2. 315.7 MW
Explanation:
1. The mechanical energy per unit mass of the river is given by:
![E_{m} = E_{k} + E_{p}](https://tex.z-dn.net/?f=%20E_%7Bm%7D%20%3D%20E_%7Bk%7D%20%2B%20E_%7Bp%7D%20)
![E_{m} = \frac{1}{2}v^{2} + gh](https://tex.z-dn.net/?f=%20E_%7Bm%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7Dv%5E%7B2%7D%20%2B%20gh%20)
Where:
Ek is the kinetic energy
Ep is the potential energy
v is the speed of the river = 3 m/s
g is the gravity = 9.81 m/s²
h is the height = 58 m
![E_{m} = \frac{1}{2}(3 m/s)^{2} + 9.81 m/s^{2}*58 m = 0.574 kJ/Kg](https://tex.z-dn.net/?f=%20E_%7Bm%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%283%20m%2Fs%29%5E%7B2%7D%20%2B%209.81%20m%2Fs%5E%7B2%7D%2A58%20m%20%3D%200.574%20kJ%2FKg%20)
Hence, the total mechanical energy of the river is 0.574 kJ/kg.
2. The power generation potential on the river is:
![P = m(t)E_{m} = \rho*V(t)*E_{m} = 1000 kg/m^{3}*550 m^{3}/s*0.574 kJ/kg = 315.7 MW](https://tex.z-dn.net/?f=%20P%20%3D%20m%28t%29E_%7Bm%7D%20%3D%20%5Crho%2AV%28t%29%2AE_%7Bm%7D%20%3D%201000%20kg%2Fm%5E%7B3%7D%2A550%20m%5E%7B3%7D%2Fs%2A0.574%20kJ%2Fkg%20%3D%20315.7%20MW%20)
Therefore, the power generation potential of the entire river is 315.7 MW.
I hope it helps you!
Answer:
Below
Explanation:
You can use this equation to find the distance :
distance = velocity x time
distance = (26.7)(3.06)
= 81.702 m
Rounding to 3 sig figs
= 81.7 m
Hope this helps
Answer:
In both cases, energy will move from an area of higher temperature to an area of lower temperature. So, the energy from room-temperature air will move into the cold water, which warms the water.
Explanation: