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slava [35]
3 years ago
14

a 4.0 kilogram ball moving at 8.0 m/s to the right collides with a 1.0 kilogram ball at rest. after the collision the 4.0 kilogr

am ball moves at 4.8 m/s to the right. what is the velocity of the 1 kilogram ball?
Physics
1 answer:
Inga [223]3 years ago
7 0
Step by step equation
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What type of specialized training is necessary to learn the skills needed to work in this career field
Nonamiya [84]

Answer:

DONTKNOW NEED CAREER FILD FIRST TO ANWSER

Explanation:

5 0
3 years ago
Imma give u all my points and ill make u brainlist jus answer them​
Reptile [31]

I'll put my answer in the comments but, part of the question is cut off do you mind putting a more readable and not sideways picture?

3 0
3 years ago
Identify the velocity-versus-time plot(s) that correspond to motion under a constant, non-zero acceleration.
ICE Princess25 [194]

Answer:

See explanation

Explanation:

The question is incomplete because the images were not attached but I will try to help you as much as possible.

Constant acceleration implies that the velocity increases uniformly with time.

The graph of constant acceleration is a straight line graph having a slope. The slope of the graph is constant at any point along the straight line.

The image attached shows a velocity-time graph depicting constant acceleration.

5 0
3 years ago
A soap bubble appears red (λ = 633nm) at the point on its front surface nearest to the viewer. Assuming n = 1.35, what is the sm
alexira [117]

Answer:

The smallest film thickness is 117 nm.

Explanation:

Light interference on thin films can be constructive or destructive. Constructive interference is dependent on the film thickness and the refractive index of the medium.

For the first interference (surface nearest to viewer), the minimum thickness can be expressed as:

2t_{min} = \frac{wavelenth}{2n}

where n is the refractive index of the bubble film.

Therefore,

2t_{min} = \frac{633x10^{-9} }{(2)(1.35)}

2t_{min} =2.344x10^{-7}

∴ t_{min} =\frac{2.344x10^{-7} }{2}

t_{min} = 1.17x10^{-7} m = 117 nm.

7 0
3 years ago
A spring balance used to weigh candy is built with a spring the spring stretches 3.00 cm when a 15 n weight is placed in the pan
ira [324]

Answer: 5.9cm

Explanation:

15N/3cm=5

Convert 3kg to N (29.42N)

Use the 5 from earlier to divide 29.42/5=5.884

Round to 5.9

5.9cm is the answer

(I don’t know if I solved this the correct way but I got it right. 5.9 is the correct answer)

6 0
3 years ago
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