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3 years ago

Identify the velocity-versus-time plot(s) that correspond to motion under a constant, non-zero acceleration.

Physics

1 answer:

ICE Princess25 [194]3 years ago

5 0

Answer:

See explanation

Explanation:

The question is incomplete because the images were not attached but I will try to help you as much as possible.

Constant acceleration implies that the velocity increases uniformly with time.

The graph of constant acceleration is a straight line graph having a slope. The slope of the graph is constant at any point along the straight line.

The image attached shows a velocity-time graph depicting constant acceleration.

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3 years ago

How far did the object travel by the end of eight seconds, according to the graph above?

Ulleksa [173]

Answer:

The object traveled 4 cm by the end of eight seconds. Correct: A)

Explanation:

Speed vs Time Graph

In a speed-time graph, speed is plotted on the vertical axis and time is plotted on the horizontal axis. If the graph is a horizontal line, the speed is constant, if the line is sloped up, the speed is increasing and the acceleration is positive and constant, and if the line is sloped down, the speed is decreasing and the acceleration is negative and constant.

The distance traveled by the object can be found by calculating the area under the graph and above the x-axis.

The graph provided shows two different zones: the first 4 seconds, the speed is constant at 1 cm/s, and the last 4 seconds, the speed is zero, i.e. the object is not moving.

The area behind the first zone is a rectangle of height 1 cm/s and base 4 sec, thus the distance is 1 * 4 = 4 centimeters.

The second zone corresponds to an object at rest, thus no distance is traveled.

The object traveled 4 cm by the end of eight seconds.

A) Correct. As shown above

B) The distance traveled is 4 cm. Incorrect

C) The distance traveled is 4 cm. Incorrect

D) The distance traveled is 4 cm. Incorrect

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3 years ago

PLS HELP FIND THE AVREGE KENETIC ENERGY!!

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3 years ago

An electron and a proton are both released from rest, midway between the plates of a charged parallel-plate capacitor. The only

topjm [15]

Answer:

Explanation:

Let the potential difference between the middle point and one of the plate be ΔV .

electric potential energy will be lost and it will be converted into kinetic energy .

Electrical potential energy lost = Vq , where q is charge on charge particle .

For proton

ΔV× q = 1/2 M V² ( kinetic energy of proton )

where M is mass and V be final velocity of proton .

For electron

ΔV× q = 1/2 m v² ( kinetic energy of electron )

where m is mass and v be final velocity of electron . Charges on proton and electron are same in magnitude .

As LHS of both the equation are same , RHS will also be same . That means the kinetic energy of both proton and electron will be same

1/2 M V² = 1/2 m v²

(V / v )² = ( m / M )

(V / v ) = √ ( m / M )

In other words , their velocities are inversely proportional to square root of their masses .

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3 years ago

An EM wave has a speed of 3 x 10 ^ 8 m/s and a wavelength of 6 x 10 ^ -7 m. What is the frequency of the wave? 90 Hz 180 Hz 2 x

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