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omeli [17]
3 years ago
5

The density of a gas is 1.25 grams/liter. Which of the following is correct to convert the density of the gas to ounce/millilite

r? [1 gram = 0.04 ounce, 1 liter = 1,000 milliliter]
A. Multiply 1.25 by 0.04 and divide the result obtained by 1,000
B. Divide 1.25 by 0.04 and multiply the result obtained by 1,000
C. Divide 1.25 by the product of 0.04 and 1,000
D. Multiply the numbers 1.25, 0.04, and 1,000
Chemistry
2 answers:
vlada-n [284]3 years ago
6 0
I am pretty positive that the answer is letter A
svp [43]3 years ago
3 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

We are given:

Density of a gas = 1.25 g/L

To convert this quantity into ounce/mililiter, we use the following conversion factors:

1 gram = 0.04 ounce

1 Liter = 1000 mili Liter

Converting the given quantity of gram/Liter into ounce/mililiter, we get:

\Rightarrow (\frac{1.25gram}{Liter})\times (\frac{0.04ounce}{1gram})\times (\frac{1Liter}{1000mL})\\\\\Rightarrow 5\times 10^{-5}ounce/mL

For the conversion, we multiply 1.25 by 0.04 and then divide the result obtained by 1000.

Hence, the correct answer is Option A.

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Answer:

the third one

Explanation:

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4 years ago
How many grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate?
Korvikt [17]

Answer: There is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

Explanation:

Chemical equation depicting reaction between sodium phosphate and aluminum carbonate is as follows.

Al_{2}(CO_{3})_{3} + 2Na_{3}PO_{4} \rightarrow 2AlPO_{4} + 3Na_{2}CO_{3}

As this equation contains same number of atoms on both reactant and product side. So, this equation is a balanced equation.

According to the equation, 2 moles of sodium phosphate is giving 3 moles of sodium carbonate.

Therefore, sodium carbonate formed by 5.3 moles of sodium phosphate is as follows.

\frac{3}{2} \times 5.3 mol\\= 7.95 mol

As number of moles is the mass of substance divided by its molar mass. So, mass of sodium carbonate ( molar mass = 105.98 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\7.95 mol = \frac{mass}{105.98 g/mol}\\mass = 842.54 g

Thus, we can conclude that there is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

8 0
3 years ago
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Charra [1.4K]
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Read 2 more answers
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