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Nadusha1986 [10]
3 years ago
11

Why echo sound cannot be heard in small room

Physics
1 answer:
Art [367]3 years ago
7 0
They can't hear an echo in small room because in it the sound can't be reflected back. For an echo of a sound to be heard,the minimum distance between the source of sound and the walls of the roomshould be 17.2 m. Obviously,in asmall room echoes cannot beheard.
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At the Indianapolis 500, you can measure the speed of cars just by listening to the difference in pitch of the engine noise betw
allsm [11]

To develop this problem it is necessary to apply the concepts related to the Dopler effect.

The equation is defined by

f_i = f_0 \frac{c}{c+v}

Where

f_h= Approaching velocities

f_i= Receding velocities

c = Speed of sound

v = Emitter speed

And

f_h = f_0 \frac{c}{c+v}

Therefore using the values given we can find the velocity through,

\frac{f_h}{f_0}=\frac{c-v}{c+v}

v = c(\frac{f_h-f_i}{f_h+f_i})

Assuming the ratio above, we can use any f_h and f_i with the ratio 2.4 to 1

v = 353(\frac{2.4-1}{2.4+1})

v = 145.35m/s

Therefore the cars goes to 145.3m/s

7 0
3 years ago
What is the answer be fast
svetlana [45]

Answer:

Explanation:

Same numbers of protons but different number of neutron so i would go for A same atomic number different number of neutrons

5 0
3 years ago
A 1.60 m tall person lifts a 2.10-kg book from the ground so it is 2.20 m above the ground. What is the potential energy of the
Viefleur [7K]

Answer:

Explanation:

Given

mass of book(m)=2.1 kg

height up to which book is lifted is (h)2.2 m

height of person (h_0)1.6 m

Potential energy of book relative to ground=mgh

PE=2.1\times 9.8\times 2.2=45.276 J

(b)PE w.r.t to person head =mg(h-h0)

=2.1\times 9.8\times (2.2-1.6)=12.348 J

work done by person in lifting box 2.2 m w.r.t floor

Word done =Potential Energy of box relative to floor=45.2 J

6 0
3 years ago
An object is dropped from the top of a tall building. At 2 seconds, it is 64 feet from the top of the building. At 4 seconds, it
jeka94

Answer:

96.21 ft/s

Explanation:

To solve this, you only need to use one expression which is:

Vf² = Vo² + 2gh

g = 9.8 m/s²

However, this exercise is talking in feet, so convert the gravity to feet first:

g = 9.8 * 3.28 = 32.15 ft/s²

Vo is zero, because it's a free fall and in free fall the innitial speed is always zero. With this, let's calculate the speed at 2 seconds, with a height of 64 ft, and then with the 256 ft:

V1 = √2*32.15*64

V1 = 64.15 ft/s

V2 = √2*32.15*256

V2 = 128.3 ft/s

So the average rate is:

V = 128.3 + 64.15 / 2

V = 96.22 ft/s

6 0
3 years ago
The sides of a cube are each of length 1. 00 m. Each side is measured with an uncertainty
astraxan [27]

The absolute uncertainty in the volume of the cube is 0.06 m³.

We need to know about the uncertainty of measurement to solve this problem. The uncertainty of cube volume can be determined by

V = s³

|ΔV| = dV/ds x Δs

where V is volume, s is length, ΔV is uncertainty in the volume and Δs is the uncertainty of length.

From the question above, we know that

s = 1.00 m

Δs = 2% of s = 2/100 x 1 = 0.02 m

By using the uncertainty of volume formula, we get

|ΔV| = dV/ds x Δs

|ΔV| = d(s³)/ds x Δs

|ΔV| = 3s² x Δs

|ΔV| = 3. 1² x 0.02

|ΔV| = 0.06 m³

Hence, the uncertainty in the volume is 0.06 m³.

Find more on uncertainty at: brainly.com/question/1577893

#SPJ4

7 0
11 months ago
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