Answer:
Angle of projection from the horizontal will be 
Explanation:
We have given that range of the projectile is 10 times the height of the projectile
Let the projectile is projected with velocity u at an angle 
Range of the projectile is equal to 
And height of the projectile is equal to 
Now according to question range is 10 times of height
So 
So angle of projection from the horizontal will be
Answer:
2.05 kgm²/s
Explanation:
I = moment of inertia of cylinder = 0.016 kgm²
r = radius of the cylinder = 6 cm = 0.06 m
v = linear speed of the cylinder = 7.7 m/s
w = angular speed of cylinder
Using the equation
v = r w
7.7 = (0.06) w
w = 128.33 rad/s
Magnitude of angular momentum of the cylinder is given as
L = I w
L = (0.016) (128.33)
L = 2.05 kgm²/s
Answer and Explanation:
In optics, a CoC(Circle of Confusion) is defined the minimum cross section of a paraxial bundle of rays made by a lens which is sphero-cylindrical type and can be viewed as an optical spot, which do not converge perfectly at the focus while a point source is being imaged due to spherical aberration.
The Circle of Confusion is also referred to as circle of indistinctness or a blur spot
Speed = (acceleration) x (time)
Velocity = (speed) in (direction of the speed)
Speed = (-3 m/s²) x (5 s) = 15 m/s
Velocity =
(15 m/s) in the direction opposite to the direction you call positive.
Displacement = (distance between start-point and end-point)
in the direction from start-point to end-point.
Distance = (1/2) (acceleration) (time)²
Distance = (1/2) (3 m/s²) (5 s)²
= (1/2) (3 m/s²) (25 s²) = 37.5 meters
Displacement =
37.5 meters in the direction opposite to the direction you call positive.
