Answer:
The value is 
Explanation:
From the question we are told that
The weight of the horizontal solid disk is 
The radius of the horizontal solid disk is 
The force applied by the child is 
The time considered is 
Generally the mass of the horizontal solid disk is mathematically represented as
=> 
=> 
Generally the moment of inertia of the horizontal solid disk is mathematically represented as
=> 
=> 
Generally the net torque experienced by the horizontal solid disk is mathematically represented as
=> 
=> 
=> 
Gnerally from kinematic equation we have that
Here 
is the initial angular velocity velocity of the horizontal solid disk which is 
So
=> 
Generally the kinetic energy is mathematically represented as
=> 
=>
Answer:
18375g
Explanation:
Let's find the volume of the rectangular block.
Volume
= length ×breadth ×height
= 3.5 ×6 ×2.5
= 52.5cm³
Mass of the block
= 350(52.5)
= 18375g
Answer:
E = 1,873 10³ N / C
Explanation:
For this exercise we can use Gauss's law
Ф = E. dA = 
/ ε₀
Where q_{int} is the charge inside an artificial surface that surrounds the charged body, in this case with the body it has a spherical shape, the Gaussian surface is a wait with radius r = 1.35 m that is greater than the radius of the sphere.
The field lines of the sphere are parallel to the radii of the Gaussian surface so the scald product is reduced to the algebraic product.
The surface of a sphere is
A = 4π r²
E 4π r² = q_{int} /ε₀
The net charge within the Gauussian surface is the charge in the sphere of q1 = + 530 10⁻⁹ C and the point charge in the center q2 = -200 10⁻⁹ C, since all the charge can be considered in the center the net charge is
q_{int} = q₁ + q₂
q_{int} = (530 - 200) 10⁻⁹
q_{int} = 330 10⁻⁹ C
The electric field is
E = 1 / 4πε₀ q_{int} / r²
k = 1 / 4πε₀
E = k q_{int}/ r²
Let's calculate
E = 8.99 10⁹ 330 10⁻⁹/ 1.32²
E = 1,873 10³ N / C
Answer:
(d) Water has a high specific heat.
Explanation:
At night, when the temperature of earth goes down due to loss of heat , the temperature of water is lost slowly and temperature of land is lost fast because of high specific heat of water . Water loses as well as gains temperature comparatively slowly due to its high specific heat .
During daytime when earth gains heat , the temperature of land rises more rapidly than water so water appears cool even during daytime when land becomes hotter . It is also due to high heat holding capacity of water or due to high specific heat of water .
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