Explanation:
n=50,r=0.02mn=50,r=0.02m,
I=5AandB=0.20TI=5AandB=0.20T
τismaxiμmwhensinθ=90∘τismaxiμmwhensinθ=90∘
τmax=niabsin90∘=mbτmax=niabsin90∘=mb
=50×5×3.14×4×10−4×2×10−1=50×5×3.14×4×10-4×2×10-1
=6.28×10−2Nm=6.28×10-2Nm
Given τ=12×τmaxτ=12×τmax
⇒sinsinθ=12⇒sinsinθ=12 or sinθ=30∘sinθ=30∘
=∠betweenareavar→randmag≠ticfield=∠betweenareavar→randmag≠ticfield.
So angle between magnetic field and the plane of the coil
=90∘−30∘=60∘=90∘-30∘=60∘.
<h3>HOPE IT HELPS </h3>
<h2>mark me in brainliest answers please please please </h2>
Answer:
1 Newton
Explanation:
F=9*10^9*q0q1/r^2]]
F=9*10^9*(q0q1)/ r^2
r=3cm
F=4N
F=9*10^9*(q0q1)/3^2
4=9*10^9*(q0q1)/9
4=10^9 q0q1
q0q1=4/10^9
q0q1=4*10^-9
To calculate the force between the forces at a distance of 6 cm
F=9*10^9*(q0q1)/ r^2
=9*10^9*(4*10^-9)/6^2
=9*10^9*(4*10^-9)/36
=10^9*4*10^-9/4
=10^9*10^-9
=1 Newton
The correct option is A: the force exerted on the wall by the sledgehammer is - 1000 N
<h3>Newton's third law</h3>
Newton's third law of motion states that for every action or force, there is an equal but oppositely directed force.
<h3>Application of the newton's third law</h3>
Force with which the sledgehammer hits the wall = 1000 N
- From the Newton's third law, an equal but oppositely directed force is exerted on the sledgehammer by the wall.
Thus, the force exerted by the sledgehammer on the wall = -1000 N
- The negative sign indicates that the force acts in a direction opposite to that of the sledgehammer.
Thus, the correct option is A: the force exerted on the wall by the sledgehammer is - 1000 N
Learn more about Newton's third law and force at: brainly.com/question/13874955
You faded out there before asking your question.
Here's some info that might be of interest:
Torque = (force) x (distance from the pivot) = (10 n) x (0.9 m) = 9 newton-meters
