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g100num [7]
3 years ago
6

Describe how a metamorphic rock might become a sedimentary rock over time.

Physics
1 answer:
andriy [413]3 years ago
7 0
<span>Metamorphic rock undergoes weathering, erosion; the particles are deposited and undergo lithification.</span>
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What is the magnitude of the kinetic frictional force
Effectus [21]

The magnitude of the kinetic friction force, ƒk, on an object is. Where μk is called the kinetic friction coefficient and |FN| is the magnitude of the normal force of the surface on the sliding object. The kinetic friction coefficient is entirely determined by the materials of the sliding surfaces. hope it helps

4 0
3 years ago
What is the momentum of a 12 kg condor flying at 6 m/s?
rusak2 [61]

Answer:

72

Explanation:

Formula

p=mv\\=12*6\\=72

5 0
3 years ago
A 10 kg bowling ball sits at the top of a 10 m hill and then slides down its icy hillside.
Nataly_w [17]
We need more informtion
5 0
3 years ago
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A 100 kg bungee jumper leaps from a bridge. The bungee cord has an un-streched equilibrium length of 10 m, and a spring constant
nika2105 [10]

Answer:

11.78meters

Explanation:

Given data

Mass m = 100kg

Length of cord= 10m

Spring constant k= 35N/m

At the greatest vertical distance, the spring potential energy is equal to the gravitational potential energy

That is

Us=Ug

Us= 1/2kx^2

Ug= mgh

1/2kx^2= mgh

0.5*35*10^2= 100*9.81*h

0.5*35*100=981h

1750=981h

h= 1750/981

h= 1.78

Hence the bungee jumper will reach 1.78+10= 11.78meters below the surface of the bridge

6 0
3 years ago
Read 2 more answers
A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/
Artemon [7]

Complete Question

A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/s2.How much force does she use to pull on the rope

Answer:

The value is  F  =  150 \  N

Explanation:

From the question we are told that

    The mass of the man is  m_m   =  75 \  kg

     The mass of the woman is  m_f  =  100 \  kg

     The acceleration of the man is  a_m  =  2.0 \  m/s ^2

Generally the force which she used to pull the rope is mathematically represented as  

           F  =  m  *  a

=>         F  =  75 *  2

=>         F  =  150 \  N

6 0
3 years ago
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