Question

At one point in space the Electric potential is measured to be 119 V at a distance of 1 meters away it is measured to be 43 V. Find the magnitude electric field.

Answer 1

Answer:

76 V/m

Explanation:

$V_{i}$ = Electric potential at initial location = 119 V

$V_{f}$ = Electric potential at final location = 43 V

$d$ = distance between initial and final location = 1 m

$E$ = magnitude of electric field

Magnitude of electric field is given as

$E = \frac{- (V_{f} - V_{i})}{d}$

$E = \frac{- (43 - 119)}{1}$

$E$ = 76 V/m