Rutherford's experiment<span> utilized positively charged alpha particles (He with a +2 charge) which were deflected by the dense inner mass (nucleus). The conclusion that could be formed from this result was that </span>atoms<span> had an inner core which contained most of the mass of an </span>atom<span> and was positively charged.</span>
The speed 
of the elevator at the beginning of the 8 m descent is nearly 4 m/s. Hence, option A is the correct answer.
We are given that-
the mass of the elevator (m) = 1000 kg ;
the distance the elevator decelerated to be y = 8m ;
the tension is T = 11000 N;
let us determine the acceleration 'a' by using Newton's second law of motion.
∑Fy = ma
W - T = ma
(1000kg x 9.8 m/s² ) - 11000N = 1000 kg x a
9800 - 11000 = 1000
a = - 1.2 m/s²
Using the equation of kinematics to determine the initial velocity.
² = ² + 2ay
= √ ( 2 x 1.2m/s² x 8 m )
= √19.2 m²/s²
= 4.38 m/s ≈ 4 m/s
Hence, the initial velocity of the elevator is 4m/s.
Read more about the Equation of kinematics:
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T=s/v=>t=1500/1,5=1000s
1,5km=1500m
Answer:
q2 = 9.02*10^{-4}C
Explanation:
To find the value of the other charge you use the Coulomb's law:
k: Coulomb's constant = 8.98*10^{9}Nm^2/C^2
q1: charge 1 = 55*10^{-6}C
r: distance between charges = 90cm = 0.9m
F: electric force = 550N
By doing q2 the subject of the formula and replacing you obtain:
hence, the value of the other charge q2 is 9.02*10^{-4}C
Explanation:
The fluctuating sound heard when two objects vibrate with different frequencies is called beats. It is given that guitar string produces 3 beats/s when sounded with a 352 Hz tuning fork and 8 beats/s when sounded with a 357 Hz tuning fork.
It is assumed to find the vibrational frequency of the string.
For 3 beats/s, beat frequency can be :
352 - 3 or 352 + 3 = 349 Hz or 355 Hz
For 8 beats/s, beat frequency can be :
357 - 8 or 357 + 8 = 349 Hz or 365 Hz
It means that the vibrational frequency is 349 Hz.
