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ss7ja [257]
3 years ago
12

The primary metallic element that's added to steel to make stainless steel is

Chemistry
1 answer:
lapo4ka [179]3 years ago
5 0
The primary element that makes steel stainless is Chromium (Cr)
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Write the equilibrium constant: Pb3(PO4)2(s) = 3Pb2+ (aq) +<br> 2PO2 (aq)
kicyunya [14]

Answer:

Kc = [Pb²⁺]³.[PO₄³⁻]²

Explanation:

Let's consider the following reaction at equilibrium.

Pb₃(PO₄)₂(s) ⇄ 3 Pb²⁺(aq) + 2 PO₄³⁻(aq)

The concentration equilibrium constant is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.

Kc = [Pb²⁺]³.[PO₄³⁻]²

This equilibrium constant is known as the solubility product of Pb₃(PO₄)₂.

7 0
3 years ago
Con has a blue-gray color.
Zielflug [23.3K]
1 is the answer. Both are made up of different particles. Same Letters of the periodic just not built the same ? (CO & CO2)& they are both odorless & colorless
4 0
3 years ago
Which answer is INCORRECT not the correct one ​
Elena L [17]

Explanation:

It's 4

Hope it's help....

<h3>^_^</h3>
6 0
3 years ago
Read 2 more answers
Calculate the molar mass of a 2.89 g gas at 346 ml, a temperature of 28.3 degrees Celsius, and a pressure of 760 mmHg.
malfutka [58]

The molar mass of gas = 206.36 g/mol

<h3>Further explanation</h3>

In general, the gas equation can be written

\large{\boxed{\bold{PV=nRT}}}

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K

T = temperature, Kelvin

mass (m)= 2.89 g

volume(V) = 346 ml = 0.346 L

T = 28.3 C + 273 = 301.3 K

P = 760 mmHg=1 atm

The molar mass (M) :

\tt PV=\dfrac{m}{M}RT\\\\M=\dfrac{mRT}{PV}\\\\M=\dfrac{2.89\times 0.082\times 301.3}{1\times 0.346}\\\\M=206.36~g/mol

8 0
3 years ago
A 12.630 g milk chocolate bar is found to contain 8.315 g of sugar. part a part complete how many milligrams of sugar does the m
kolezko [41]
Answer:
A 12.630 bar of chocolate contains 8315 milligrams of sugar

Explanation:
From the basics of conversion, we can find that:
1 gram is equal to 1000 mg
Using cross multiplication, we can find how many milligrams are present in 8.315 grams as follows:
1 gram .............> 1000 mg
8.315 grams ....> ?? mg
amount in milligrams = (8.315*1000) / 1 = 8315 milligrams

Hope this helps :)
5 0
4 years ago
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