Answer:
Fluorine has seven electrons in 2p-subshell whereas chlorine has seven electrons in its 3p-subshell. 3p-subshell is relatively larger than 2p-subshell. Therefore, repulsion among the electrons will be more in the 2p-shell of fluorine than 3p-subshell in chlorine. Due to the smaller size and thus, the greater electron-electron repulsions, fluorine will not accept an incoming electron with the same as chlorine.
Answer:
An increase
Explanation:
The strong southerly winds affect the vapor pressure by increasing it .
When the vapor pressure increases it means an increase in temperature and more evaporation occurs.
A decrease in the vapor pressure means a reduction in temperature with less amount of evaporation being involved
The hydrogen bonding in H₂O is stronger than that of HF
Explanation:
Hydrogen bonds are special dipole-dipole attraction in which electrostatic attraction is established between hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.
- The strength of hydrogen bonds depends on the how electronegative an atom is.
- Electronegativity refers to the tendency of an atom to gain electrons.
- The higher the value, the higher the tendency.
- This why oxygen with a higher electronegativity will form a stronger hydrogen bond with hydrogen compared to fluorine.
Learn more:
hydrogen bond brainly.com/question/12408823
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