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ss7ja [257]
3 years ago
12

The primary metallic element that's added to steel to make stainless steel is

Chemistry
1 answer:
lapo4ka [179]3 years ago
5 0
The primary element that makes steel stainless is Chromium (Cr)
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8. Thermal Energy is?
Burka [1]

Thermal energy is the sum of the kinetic and potential energy of all the particles in an object. The figure shows that if either potential or kinetic energy increases, thermal energy increases.

hope it really helps...!!!

4 0
2 years ago
Iron has a mass of 7.87 g per cubic centimeter of volume, and the mass of an iron atom is 9.27 × 10-26 kg. If you simplify and t
Talja [164]
<span>(a) what is the average volume (in cubic meters) required for each iron atom
For this case, the density of Iron would be </span>7.87g/cm³
<span>
V = 9.27 x 10^-26 kg / </span>7.87g/cm<span>³ ( 1 kg / 1000 g)
</span>V = 1.18 x 10-23 cm³<span>

(b) what is the distance (in meters) between the centers of adjacent atoms?
We assume the atoms as cube, so we use the volume of the cube to calculate the distance of the atoms.

V = </span>1.18 x 10-23 cm<span>³ = s</span>³
s = 2.28 x 10^-8 cm
7 0
2 years ago
Read 2 more answers
What is Oxidation state of sulphur in Na2S4O6?Help me..​
quester [9]

Answer:

oxidation state of sulphur=x

Explanation:

Na2S4O6=2[+1]+4x+6[-2]=0

                 +2+4x-12=0

                     4x-10=0

                           4x=10

                            x=10/4=2.5

6 0
2 years ago
11. In TLC analysis of ferrocene and acetylferrocene (on silica TLC plate) which prediction is correct: A) ferrocene is more pol
yaroslaw [1]

Answer:

Alternative C would be the correct choice.

Explanation:

  • The dual compounds were evaluated on something like a TLC plate through three separate additives in conducting a TLC study of ferrocene versus acetylferrocene.
  • The polar as well as nonpolar ferrocene where nonpolar is about 0.63 with the maximum R_f value, and indeed the polar is somewhere around 0.19 with R_f.
  • TLC plate (30:1 toluene/ethanol) established with.  

The other three choices are not related to the given circumstances. So that option C would be the appropriate choice.

8 0
2 years ago
Question 15 How many grams of NaCl are required to make 500.0 mL of a 1.500 M solution? 58.40 g 175.3 g 14.60 g 43.83 g
ExtremeBDS [4]
Hi!

To make 500 mL of a 1,500 M solution of NaCl you'll require 43,83 g

To calculate that, you will need to use a conversion factor to go from the volume of the 1,500 M solution to the required grams. For this conversion factor, you'll use the definition for Molar concentration (M=mol/L) and the molar mass of NaCl. The conversion factor is shown below:

gNaCl=500mLsol* \frac{1L}{1000 mL}* \frac{1,500 mol NaCl}{1Lsol}* \frac{58,4428 g NaCl}{1 mol NaCl} \\ =43,83gNaCl

Have a nice day!
4 0
3 years ago
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