Answer:
dipole-dipole interactions.
Explanation:
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Explanation:
I am not understanding your question
A bowling ball.
definition of dense-closely compacted in substance
We know,
AgNO3 + NaCl ⇒ NaNO3 + AgCl(s)
The moles of Na+ present:
0.5 L * 0.001 mol/L
= 5 x 10⁻⁴ mol
Moles of Ag+ present:
0.5 * 0.02
= 0.01 mol
The limiting reactant is Na
Therefore, the moles of Ag reacted:
5 x 10⁻⁴
AgCl is insoluble in water; therefore, the AgCl formed will precipitate
1 ounces ----------- 29.5735 mL
5 ounces ----------- ??
5 x 29.5735 / 1 => 147.868 mL
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