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maks197457 [2]
1 year ago
9

-

Chemistry
1 answer:
QveST [7]1 year ago
8 0

Answer:

: The conductivity of electrolyte solutions: (a) 0.1 M NaCl (b) 0.05 M NaCl (c) 0.1 M HgCl2. An electrolyte solution conducts electricity because of the movement of ions in the solution (see above). The larger the concentration of ions, the better the solutions conducts. Weak electrolytes, such as HgCl2, conduct badly because they produce few ions when dissolved (low concentration of ions) and exist mainly in the form of molecules.

Explanation:

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Does anyone know how to do this?
rjkz [21]

Answer:

I know

Explanation:

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3 0
3 years ago
A sailboat is pushed by a steady wind with a force of 4000 N. Its acceleration is 2
AveGali [126]

Answer:

<h2>2000 kg</h2>

Explanation:

The mass of the sailboat can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{4000}{2}  \\

We have the final answer as

<h3>2000 kg</h3>

Hope this helps you

6 0
3 years ago
A volume of 300 milliliters of water is added to a liter of water. What is the final volume of water, in milliliters?
Hatshy [7]

Answer:

1L=1000mL

1000mL+300mL=1300mL

so the answer is d.1300mL

Explanation:

7 0
3 years ago
Read 2 more answers
What is ΔG° at 298 K for the following equilibrium? Ag+(aq) + 2NH3(aq) Ag(NH3)2+(aq); Kf = 1.7 × 107 at 298 K a. 41 kJ b. 0 c. –
jekas [21]

Answer:

ΔG° = 41.248 KJ/mol (298 K); the correct answer is a) 41 KJ

Explanation:

Ag+(aq)  +  2NH3(aq)  ↔ Ag(NH3)2+(aq)

⇒ Kf = 1.7 E7; T =298K  

⇒ ΔG° = - RT Ln Kf.....for aqueous solutions

∴ R = 8.314 J/mol.K

⇒ ΔG° = - ( 8.314 J/mol.K ) * ( 278 K ) ln ( 1.7 E7 )

⇒ ΔG° = 41248.41 J/mol * ( KJ / 1000J )

⇒ ΔG° = 41.248 KJ/mol

7 0
3 years ago
Read 2 more answers
What is the [Na2SO4] (MM = 142.04 g/mol) in ppt if 100.00 mL of a
Ugo [173]

Answer:

1.345

Explanation:

I THINK SORRY

7 0
2 years ago
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