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maks197457 [2]
1 year ago
9

-

Chemistry
1 answer:
QveST [7]1 year ago
8 0

Answer:

: The conductivity of electrolyte solutions: (a) 0.1 M NaCl (b) 0.05 M NaCl (c) 0.1 M HgCl2. An electrolyte solution conducts electricity because of the movement of ions in the solution (see above). The larger the concentration of ions, the better the solutions conducts. Weak electrolytes, such as HgCl2, conduct badly because they produce few ions when dissolved (low concentration of ions) and exist mainly in the form of molecules.

Explanation:

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Which physical property will change if the amount of the sample changes?​
kramer

Answer:

Extensive Properties

Explanation:

A physical property that will change if the amount of matter changes. Change in which the matter's physical appearance is altered, but composition remains unchanged. Solid is distinguished by a fixed structure. Its shape and volume do not change.

6 0
3 years ago
Calculate the theoretical yield for the bromination of both stilbenes
podryga [215]

Answer:

cinnamic acid - 150 mg

cis-stilbene - 100 μL

trans- stilbene - 100 mg

pyridinium tribromide - 200-385 mg

For this data:

moles of cinnamic acid = 0.150 g/148.16 g/mol = 0.001 mols

Theoretical mass of dibromoproduct formed = 0.001 mol x 307.97 g/mol = 0.312 g

cis-stilbene (100 ul = 0.1 ml)

moles of cis-stilbene = 0.1 ml x 1.01 g/mol/180.25 g/mol = 0.00056 mols

Theoretical mass of dibromoproduct formed = 0.00056 mol x 340.05 g/mol = 0.19 g

trans-stilbene

moles of tran-stilbene = 0.1 g/180.25 g/mol = 0.00055 mols

Theoretical mass of dibromoproduct formed = 0.00055 mol x 340.05 g/mol = 0.19 g

Explanation:

4 0
2 years ago
Would any Chemistry braniacs be kind enough to help explain how to work these out? Any help is appreciated, thanks
o-na [289]

Answer:

NO.3) Mass of Al2O3 formed = 229.5g

7 0
2 years ago
Complete the reaction, which is part of the electron transport chain. The abbreviation Q represents coenzyme Q. Use the appropri
fredd [130]

Answer:

x = 2+

Explanation:

1) FADH2 + Q => FAD + QH2

Since H is added to Q

=> Reactant reduced is Q

(2) Balancing charges on both sides of the equation gives:

QH2 + 2 cyt c(Fe3+) => Q + 2 cyt c(Fe2+) + 2 H+

Thus x = 2+

7 0
3 years ago
The equilibrium constant for the reaction 2NO2(g) N2O4(g) is Keq = . If a sample at equilibrium was found to contain 0.058 M NO2
Sladkaya [172]

Answer:

\boxed{3.6}

Explanation:

                  2NO₂ ⇌ N₂O₄

E/mol·L⁻¹:   0.058     0.012

K_{\text{eq}} = \dfrac{\text{[N$_{2}$O$_{4}$]}}{\text{[NO$_{2}$]$^{2}$}} = \dfrac{0.012}{0.058^{2}} = \mathbf{3.6} \\\\

\text{The $K_{\text{eq}}$ value would be $\boxed{\mathbf{3.6}}$}

7 0
3 years ago
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