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jekas [21]
3 years ago
6

Binary ionic and binary molecular compounds have what two things that are similar in their composition

Chemistry
1 answer:
Sonbull [250]3 years ago
3 0
Best Answer: Ionic binary compounds -- contain a metal cation and an anion made of a nonmetal or a polyatomic anion. Consider calcium phosphate:
Ca = 2+ (Group IIA)
PO4 = 3- (phosphate)
The lowest common multiple of 2+ and 3- is 6. You must have 3 Ca2+ to make +6; you must have 2 PO43- to make -6. The sum of the positive and negative charges must be equal in a compound because they are electrically neutral.
Ca3(PO4)2 -- calcium phosphate

Binary molecular compounds -- contain two or more nonmetals bonded covalently. There are no ions present because the atoms share electrons. Prefixes are used to indicate the number of atoms of each kind present. Examples are:
SO2 -- sulfur dioxide
N2O4 -- dinitrogen tetraoxide
PCl3 -- phosphorous trichloride
CO -- carbon monoxide

The general formula for an acid is HX, where X is an anion. Binary acids contain H and a nonmetal and are named with the prefix "hydro" and the suffix "ic". Examples are:
HCl -- hydrochloric acid
H2S -- hydrosulfuric acid
HF -- hydrofluoric acid
Ternary acids contain H and a polyatomic anion. Examples are:
H2SO4 -- sulfuric acid
HNO3 -- nitric acid
HNO2 -- nitrous acid
HClO3 -- chloric acid
HClO2 -- chlorous acid
HClO -- hypochlorous acid
The names of the anions are changed as follows:
-ate anions form -ic acids
-ite anions form -ous acids
per...ate anions form per...ic acids
hypo...ite anions form hypo...ous acids.
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The combustion of ammonia in the presence of excess oxygen yields no2 and h2o: 4 nh3 (g) + 7 o2 (g) â 4 no2 (g) + 6 h2o (g) the
VLD [36.1K]
The answer would be 118.68 g.
Explanation for this is:4 moles of NH3 give 4 moles of NO2 
so 1mole of NH3 will give 1 mole of NO2 
43.9 grams of NH3 contains 2.58 moles 
so 2.58 moles will be produced of NO2 
which is 118.7 grams this the amount of oxygen that is used.
8 0
3 years ago
A. 25.0 ml of a solution of sodium hydroxide solution required 21.50 ml of 0.100 mol/l sulphuric acid for neutralisation.
nexus9112 [7]

The concentration of the sodium hydroxide solution in mol/l is 0.176 M.

Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.

Given

V =25 ml = 0.025 L

M = 0.1

C₁ = 0.1

V₁ = 21.50 = 0.022 L

C₂ = ?

V₂ = 25 ml = 0.025 L

C₁V₁ = C₂V₂

C₂ = C₁V₁ / V₂

   = 0.1 * 0.022 * 2 / 0.025

   =  0.176 M

The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.

The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.

Learn more about concentration here:-brainly.com/question/26255204

#SPJ1

3 0
1 year ago
How many grams of oxygen would be needed to completely react with 18 grams of methane (CH4)?
S_A_V [24]

Answer:

35.91 grams of oxygen

Explanation:

6 0
3 years ago
Gaseous methane (CH4) reacts with gaseous oxygen gas (02) to produce gaseous carbon dioxide (CO2) and gaseous water (H20). What
Mariana [72]

Answer:

Theoretical yield = 3.51 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For CH_4  :-

Mass of CH_4  = 1.28 g

Molar mass of CH_4  = 16.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.28\ g}{16.04\ g/mol}

Moles_{CH_4}= 0.0798\ mol

For O_2  :-

Mass of O_2  = 10.1 g

Molar mass of O_2  = 31.998 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{10.1\ g}{31.998\ g/mol}

Moles_{O_2}= 0.3156\ mol

According to the given reaction:

CH_4+2O_2\rightarrow CO_2+2H_2O

1 mole of methane gas reacts with 2 moles of oxygen gas

0.0798 mole of methane gas reacts with 2*0.0798 moles of oxygen gas

Moles of oxygen gas = 0.1596 moles

Available moles of oxygen gas = 0.3156 moles

<u>Limiting reagent is the one which is present in small amount. Thus, CH_4 is limiting reagent. </u>

The formation of the product is governed by the limiting reagent. So,

1 mole of methane gas on reaction produces 1 mole of carbon dioxide.

0.0798 mole of methane gas on reaction produces 0.0798 mole of carbon dioxide.

Mole of carbon dioxide = 0.0798 mole

Molar mass of carbon dioxide = 44.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0798\ moles= \frac{Mass}{44.01\ g/mol}

Mass of CO_2 = 3.51 g

<u> Theoretical yield = 3.51 g</u>

3 0
3 years ago
If the density of a liquid 102g/cm^3, how many milligrams will be in 63 mL of that liquid?
Ede4ka [16]

Answer:

<h2>6426000 mg</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question

63 mL = 63 cm³

We have

mass = 102 × 63 = 6426

But 1 g = 1000 mg

6426 g = 6426000 mg

We have the final answer as

<h3>6,426,000 mg</h3>

Hope this helps you

6 0
2 years ago
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