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Katarina [22]
3 years ago
9

A scientist would most likely need to update her model when it

Chemistry
2 answers:
NeTakaya3 years ago
7 0

Answer:

When the model no more supports the latest results.

Explanation:

Model is the term used for the demonstration of a system or an idea, a process of an object that has an application in illustrating and demonstrating a phenomenon. The central models are used by the scientists for both in research and in communicating an explanation. The models are used by the scientists to offer the way on how to illustrate data in order to demonstrate it as a hypothesis. However, scientists are required to update their models when it no longer supports the present results.

Marizza181 [45]3 years ago
5 0
A scientist would most likely need to update her model when it no longer supports the latest results.
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Which situation would cause the following equilibrium reaction to decrease the formation of the products? 2SO2 (g) + O2 (g) Two
vovangra [49]

The given equilibrium reaction is,

2 SO_{2} (g) + O_{2}(g)  2 SO_{3} (g) + Energy

The given reaction is exothermic. So, heat energy will be a product. Therefore, decreasing the temperature (heat energy) would lead to the formation of more products as when the amount of energy which is a product is reduced, there is more room for the products to form.

Increasing the pressure would shift the equilibrium towards that side which has least number of moles of the gaseous substance. Hence, here increasing the pressure would lead to the formation of more products by shifting the equilibrium towards the right side.

Decreasing the volume would make the equilibrium shift towards the least number of moles of the gaseous substance. So, here in this equilibrium decreasing the volume would lead to the formation of more products.

8 0
3 years ago
Read 2 more answers
The word eclipse most closely means to
Gennadij [26K]

Answer:

OD) Block the view of

Explanation:

3 0
3 years ago
If the theoretical yield of a reaction is 0.110 g and the actual yield is 0.104 g , what is the percent yield?
Westkost [7]
Theoretical Yield is an Ideal yield with 100 % conversion of reactant to product. It is in fact a paper work.

While,

Actual Yield is the yield which is obtained experimentally. It is always less than theoretical yield because it is not possible to have 100% conversion of reactants into products. Even some amount of product is lost while handling it during the process.

Percentage Yield is Calculated as,

                    %age Yield  =  Actual Yield / Theoretical Yield × 100

Data Given:
                   Actual Yield  =  0.104 g

                   Theoretical Yield  =  0.110 g

Putting Values,

                    %age Yield  =  0.104 g / 0.110 g × 100

                    %age Yield  =  94.54 %
3 0
3 years ago
An aqueous solution is listed as being 33.8% solute by mass with a density of 1.15 g/mL, the molar mass of the solute is 145.6 g
vodomira [7]

Answer:

A) 2.69 M

B) 0.059

Explanation:

A) We have:

33.8% solute by mass= 33.8 g solute/100 g solution

molarity = mol solute/ 1 L solution

molarity= \frac{33.8 g solute}{100 g solution} x \frac{1.15 g solution}{1 ml} x \frac{1 mol solute}{145.6 g solute} x \frac{1000 ml}{1 L}

molarity= 2.69 mol solute/L solution = 2.69 M

B) We know that there are 33.8 g of solute in 100 g of solution.

As the total solution is compounded by solute+solvent (in this case, solvent is water), the mass of water is the difference between the mass of the total solution and the mass of solute:

mass of water= 100 g - 33.8 g = 66.2 g

Now, we calculate the number of mol of both solute and water:

mol solute= 33.8 g solute x \frac{1 mol solute}{145.6 g} = 0.232 mol

mol H20= 66.2 g H₂O x \frac{1 mol H2O}{18 g}

Finally, the mol fraction of solute (Xsolute) is calculated as follows:

Xsolute=\frac{mol solute}{total mol}= \frac{mol solute}{mol solute + mol H2O}=\frac{0.232 mol}{0.232 mol + 3.677 mol}

Xsolute= 0.059

4 0
3 years ago
Which of the following is true about mixtures?
Hatshy [7]
The correct answer is D. Mixtures can be easily separated solutions cannot.
8 0
3 years ago
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