1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brums [2.3K]
3 years ago
9

How many electrons are in a atom of zicronium

Chemistry
2 answers:
Karo-lina-s [1.5K]3 years ago
5 0

Answer:

Name Zirconium

Atomic Mass 91.224 atomic mass units

Number of Protons 40

Number of Neutrons 51

Number of Electrons 40

Explanation:

MrRissso [65]3 years ago
3 0

Answer:

There are 40 electrons in one atom of Zirconium.

Explanation:

Note: The word is not zicronium, it is Zirconium.

You might be interested in
What is the answer helpnme plz
kykrilka [37]
MgH2 + 2 H2O → Mg(OH)2 + 2 H2
8 0
2 years ago
Which is best represented by the equation?
sergeinik [125]
A- law of conservation of energy
3 0
3 years ago
Name the type of chemical reaction that occurs when magnesium chloride solution reacts with sodium carbonate solution
Svetlanka [38]

Answer:

precipitation reaction

8 0
3 years ago
Read 2 more answers
What does a neutralization reaction produce?
algol13

Answer:

hope this help....

Explanation:

Neutralization is the reaction of an acid and a base, which forms water and a salt. Net ionic equations for neutralization reactions may include solid acids, solid bases, solid salts, and water.

7 0
2 years ago
Read 2 more answers
If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of H2SO4(aq)? For your ans
Alik [6]

Question is incomplete, complete question is;

A 34.8 mL solution of H_2SO_4 (aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).

H_2SO_4(aq)+2NaOH(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)

If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of H_2SO_4(aq)? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.

Answer:

0.044 M is the molarity of H_2SO_4(aq).

Explanation:

The reaction taking place here is in between acid and base which means that it is a neutralization reaction .

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_1,M_2\text{ and }V_2  are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=34.8 mL\\n_2=1\\M_2=0.15 M\\V_2=20.4 mL

Putting values in above equation, we get:

2\times M_1\times 34.8 mL=1\times 0.15 M\times 20.4 mL\\\\M_1=\frac{1\times 0.15 M\times 20.4 mL\times 10}{2\times 34.8 mL}=0.044 M

0.044 M is the molarity of H_2SO_4(aq).

4 0
3 years ago
Other questions:
  • What is the mass of 1.0 x 10-3 mole of Zn? 3.9 x 1022 0.065 0.000015
    14·2 answers
  • Which energy source contributes to the greatest emissions of gases in the environment during the energy production process
    12·1 answer
  • The fundamental particles of protons and neutrons are called....
    9·2 answers
  • Please answer this, <br>Determine the weight of CaO produced by heating 70 g of CaCO3
    7·1 answer
  • Is be2+ stable or not?<br> is Ne stable or not?<br> is Br- stable or not?<br> is h+ stable or not?
    12·2 answers
  • Can you balance the following oxidation-reduction reaction and indicate which atoms have undergone oxidation and reduction? ____
    15·2 answers
  • Which of the following statements are TRUE? Group of answer choices Dynamic equilibrium indicates that the amount of reactants a
    12·1 answer
  • How are you finding the moles of the unknown substance when you are only given the grams of the unknown molecular compound?
    7·1 answer
  • Calculate h30+ for a 8.86*10^3 hbr solution
    13·1 answer
  • Which country had the highest number of sales
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!