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3 years ago

9

What happens when limestone is heated

2 answers:

babymother [125]3 years ago

7 0

It breaks into calcium oxide and carbon di oxide.

Neko [114]3 years ago

3 0

Limestone; When used to form lime, a sedimentary rock is composed of calcium carbonate salts. The other name of limestone is limestone. In the structure of at least 90% CaCO3 (calcium carbonate) is called the principal limestone rocks. Limestone, cement used in construction.

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A reaction mixture that consisted of 0.35 molH2and 1.6 mol I2 was introduced into a 2 L flask and heated. At the equilibrium, 60

Ann [662]

Answer:

The equilibrium constant Kc for the reaction is :

<u>16.07 </u>

<u></u>

Explanation:

The balanced equation is :

$H_{2}(g)+I_{2}(g)\rightleftharpoons 2HI(g)$

First ,

"At the equilibrium, 60% of the hydrogen gas had reacted"

This means the degree of dissociation = 60% = 0.6

Here we are denoting degree of dissociation by ="x" = 0.6

Now , consider the equation again,

$H_{2}(g)+I_{2}(g)\rightleftharpoons 2HI(g)$

H2 I2 2HI

0.35 1.6 0 (Initial Concentration)

0.35(1 - x) 1.6(1 - x) 2x (At equilibrium)

0.35(1 - 0.6) 1.6(1 - 0.6) 2(0.6)

0.14 0.64 1.2

calculate the concentration of each:

$Concentration =\frac{moles}{Volume(L)}$

$C_{H_{2}}=\frac{0.14}{2}$

$C_{H_{2}}=0.07moles/L$

$C_{I_{2}}=\frac{0.64}{2}$

$C_{I_{2}}=0.32moles/L$

$HI=\frac{1.2}{2}$

$HI=0.6moles/L$

The equilibrium constant for this reaction "Kc" can be written as:

$Kc=\frac{[HI]^{2}}{[H_{2}][I_{2}]}$

$Kc=\frac{0.6^{2}}{0.07\times 0.32}$

$Kc=\frac{0.36}{0.0224}$

$Kc=16.07$

3 0

3 years ago

A cube made of platinum (Pt) has an edge length of 1.0 cm. (a) Calculate the number of Pt atoms in the cube. (b) Atoms are spher

irina1246 [14]

Answer:

a)The total number of platinum atoms are $6.620\times 10^{22} atoms$ .

b)The radius of a Pt atom is 138.7 pm.

Explanation:

a) Let the total number of platinum atoms be x

And mass of x atoms of platinum be m

Edge length of platinum cube ,s= 1.0 cm

Volume of the cube = $1.0 cm^3$

Density of the platinum cube = $d=21.45 g/cm^3$

Mass = Density × Volume

$(m)=21.45 g/cm^3\times 1.0 cm^3=21.45 g$

Mass of an atom of platinum = $3.240\times 10^{-22} g$

$x\times 3.240\times 10^{-22} g=21.45 g$

$x=6.620\times 10^{22} atoms$

b) If only 74 percent of the space inside the cube is taken up by Pt atoms.

Volume occupied by platinum atoms = 74% of $1.0 cm^3$

$V'= 0.74 cm^3$

Volume occupied by $6.620\times 10^{22}$ atoms is $0.74 cm^3$ .

$6.620\times 10^{22} \times \frac{4}{3}\pi r^3=V'$

$6.620\times 10^{22} \times \frac{4}{3}\times 3.14\times r^3=0.74 cm^3$

$r = 1.387\times 10^{-8} m = 138.7 pm$

The radius of a Pt atom is 138.7 pm.

3 0

3 years ago

How many molecules of CH4 are in 24.1 g of this compound?

jok3333 [9.3K]

<u>1) find molar mass of CH₄</u>

$=12.01+4(1.01)\\\\=16.05\ g/mol$

<u>2) determine moles of CH₄</u>

$=24.1g\ CH_{4}\ x\ \frac{1\ mol\ CH_{4}}{16.05g\ CH_{4}}\\\\=1.501557632\ mol\ CH_{4}$

<u>3) multiply by avogadro's number</u>

$=1.501557632\ mol\ CH_{4}\ x\ \frac{6.022\ x\ 10^{23}\ molecules\ CH_{4}}{1\ mol\ CH_{4}} \\\\=9.04238006\ x\ 10^{23}\\\\=9.04\ x\ 10^{23}\ molecules\ CH_{4}$

7 0

2 years ago

4.00 dm of oxygen at a pressure of 2 atm and 1.00 dm3 nitrogen at a pressure of 1 atm are introduced into a 2.00 dm3 vessel.

podryga [215]

Answer:

A

Explanation:

5 0

3 years ago

2. The Food and Drug Administration (FDA) mandates that all vinegar sold in the United States must have a minimum concentration

Scilla [17]

Answer:

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

Explanation:

4% acetic acid by mass means that 4 gram of acetic acid in 100 g solution.

Given that density of the vinegar is same is that of water = 1 g/mL

Mass of the vinegar solution = 100 g

Volume of the vinegar solution = V

$Density=\frac{Mass}{Volume}$

$1 g/mL=\frac{100 g}{V}$

V = 100 mL = 0.1 L

Moles of acetic acid = $\frac{4 g}{60.052 g/mol}=0.0666 mol$

$Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}$

$M=\frac{0.0666 mol}{0.1 L}=0.6660 mol/L$

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

4 0

3 years ago