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3 years ago

Which of the following is not a valid conversion factor? 1/100 centimeter 1mL/1cm^3 1kilometer/1000 meters 1meter/10 milimeters

2 answers:

8 0

1meter/10 milimeters which should be 1000 mm

1m=1000mm

International System of Units (SI Units) are organized body of measurements for physical quantity. They are set to be the norm or global norm scaling for every physical quantity which includes kilogram, meter, second, ampere, kelvin, candela and mole. These measurements then can increase or decrease by the power of ten, multiplied or divided. As said and explained, the SI is helpful in describing objects because 
1. They give us the idea of how much matter is contained in that single substance or the current state the matter is in or how hot or cold. We measure and can quantify the quality of the specific matter. 
2. SI Units are a global set of measurement hence, we can communicate with ease from western to eastern countries with these measurements without having problems in terms of portraying or displaying a set of physical quantities.

Romashka-Z-Leto [24]3 years ago

4 0

Answer:hello

Explanation:

Task masters

Is correct! It should be answer(4) or (D)

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The breeding of animals is necessary to produce

Aneli [31]

Animal breeding is the process of selective mating of animals with desirable genetic traits, to maintain these traits in future generations.

6 0

3 years ago

What is the full meaning of DR.HERC

Sedaia [141]

Answer:

Determine the problem

Gather Research

Form a Hypothesis

Carry out an experiment

Record and analyse the results

Summarise the outcome in a Conclusion

Explanation:

Hope this helps :D

5 0

3 years ago

Read 2 more answers

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som

jek_recluse [69]

The question is incomplete, the complete question is:

A certain substance X has a normal freezing point of $-6.4^oC$ and a molal freezing point depression constant $K_f=3.96^oC.kg/mol$ . A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at $-13.6^oC$ . Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.

Answer: The mass of glycine that can be dissolved is $1.3\times 10^2g$

Explanation:

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

$\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m$

$\text{Freezing point of pure solvent}=\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}$ ......(1)

where,

Freezing point of pure solvent = $-6.4^oC$

Freezing point of solution = $-13.6^oC$

i = Vant Hoff factor = 1 (for non-electrolytes)

$K_f$ = freezing point depression constant = $3.96^oC/m$

$m_{solute}$ = Given mass of solute (glycine) = ?

$M_{solute}$ = Molar mass of solute (glycine) = 75.07 g/mol

$w_{solvent}$ = Mass of solvent = 950. g

Putting values in equation 1, we get:

$-6.4-(-13.6)=1\times 3.96\times \frac{m_{solute}\times 1000}{75.07\times 950}\\\\m_{solute}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\m_{solute}=129.66g=1.3\times 10^2g$

Hence, the mass of glycine that can be dissolved is $1.3\times 10^2g$

5 0

3 years ago

The temperature on Mercury may drop to –263 °F at night. What is this temperature in degrees Celsius?

jenyasd209 [6]

It would be -163.889 degrees Celsius!

6 0

3 years ago

Read 2 more answers

A 4.00g sample of helium has a volume of 24.4L at a temperature of 25.0 C and a pressure of 1.00 atm. The volume of the helium i

Leona [35]

Answer:

0.852 mol

Explanation:

First we convert 4.00 g of helium (He) into moles, using its molar mass:

4.00 g ÷ 2 g/mol = 2 mol He

To answer this problem we can use Avogadro's law, which states that at constant pressure and temperature:

V₁n₂=V₂n₁

Where:

V₁ = 24. 4 L

n₂ = ?

V₂ = 10.4 L

n₁ = 2 mol

We input the data:

24.4 L * n₂ = 10.4 L * 2 mol

And solve for n₂:

n₂ = 0.852 mol

3 0

3 years ago