Answer:
![1.75\cdot 10^{-4} M](https://tex.z-dn.net/?f=1.75%5Ccdot%2010%5E%7B-4%7D%20M)
Explanation:
Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:
![S = k_H p^o](https://tex.z-dn.net/?f=S%20%3D%20k_H%20p%5Eo)
Where
is Henry's law constant.
Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.
Given initially:
![S_1 = 2.67\cdot 10^{-4} M](https://tex.z-dn.net/?f=S_1%20%3D%202.67%5Ccdot%2010%5E%7B-4%7D%20M)
Also, at sea level, we have an atmospheric pressure of:
![p = 1.00 atm](https://tex.z-dn.net/?f=p%20%3D%201.00%20atm)
Given mole fraction:
![\chi_{O_2} = 0.209](https://tex.z-dn.net/?f=%5Cchi_%7BO_2%7D%20%3D%200.209)
According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:
![p^o = \chi_{O_2} p](https://tex.z-dn.net/?f=p%5Eo%20%3D%20%5Cchi_%7BO_2%7D%20p)
Then the equation becomes:
![S_1 = k_H \chi_{O_2} p](https://tex.z-dn.net/?f=S_1%20%3D%20k_H%20%5Cchi_%7BO_2%7D%20p)
Solve for
:
![k_H = \frac{S_1}{\chi_{O_2} p} = \frac{2.67\cdot 10^{-4} M}{0.209\cdot 1.00 atm} = 0.001278 M/atm](https://tex.z-dn.net/?f=k_H%20%3D%20%5Cfrac%7BS_1%7D%7B%5Cchi_%7BO_2%7D%20p%7D%20%3D%20%5Cfrac%7B2.67%5Ccdot%2010%5E%7B-4%7D%20M%7D%7B0.209%5Ccdot%201.00%20atm%7D%20%3D%200.001278%20M%2Fatm)
Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:
![p = 0.657 atm](https://tex.z-dn.net/?f=p%20%3D%200.657%20atm)
Apply Henry's law using the constant we found:
![S_2 = k_H \chi_{O_2} p = 0.001278 M/atm\cdot 0.209\cdot 0.657 atm = 1.75\cdot 10^{-4} M](https://tex.z-dn.net/?f=S_2%20%3D%20k_H%20%5Cchi_%7BO_2%7D%20p%20%3D%200.001278%20M%2Fatm%5Ccdot%200.209%5Ccdot%200.657%20atm%20%3D%201.75%5Ccdot%2010%5E%7B-4%7D%20M)
Answer is: pressure of oxygen is 31,3 kPa.
The total pressure<span> of an ideal gas mixture is the sum of the </span>partial pressures<span> of the gases in the mixture.
p(mixture) = p(helium) + p(oxygen) + p(carbon dioxide).
p(oxygen) = p(mixture) - (p(helium) + p(carbon dioxide)).
p(oxygen) = 101,4 kPa - (68,7 kPa + 1,4 kPa).
p(oxygen) = 101,4 kPa - 70,1 kPa.
p(oxygen) = 31,3 kPa.
</span>
Let x be the volume of fluid removed and the volume of pure antifreeze that is added. The concentration of antifreeze in the fluid is 0.3, the concentration in pure antifreeze is 1 and that in the final solution is 0.4 The volume of the final solution is 10.
(10 - x)(0.3) + x = 10(0.4)
0.3 + 0.7x = 0.4
x = 1/7 quarts
The volume that should be drained is 1/7 quarts
Answer:
D. The frictional force overcomes the force that binds the electrons to the atoms, enabling the electrons to move elsewhere
Explanation:
Neutral objects becomes charged by rubbing them together due to the frictional force which overcomes the attractive force holding electrons together in an atom.
Friction is the resistance to flow or movement. When we rub bodies together, the movement of electrons becomes inhibited and this can cause an orbital electron loosely held in an atom to be pulled off as the force of friction increases. This mechanism would result in a body losing electron and another readily gaining that electron as they interact. The loss and gain of electrons causes a neutral body to become charged.
I’m pretty sure D transverse