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adelina 88 [10]
2 years ago
10

Question 26 suppose that a constant force is applied to an object. newton's second law of motion states that the acceleration of

the object varies inversely with its mass. a constant force acting upon an object with mass 14 kg produces an acceleration of 3 /ms2 . the acceleration of another object produced by the same force is 7 /ms2 . what is the mass of this object?
Physics
1 answer:
ololo11 [35]2 years ago
4 0

<span>The answer is 6 kg the mass of the second object. By using Inversely proportional formula it means that (14 kg) (3 m/s</span>²<span>) = M (7 m/s</span>²<span>). Where M is the mass of the second object. For the Newton’s second law of motion formula which is: Force = mass x acceleration, we have:</span>

<span>F = (14 kg) (3 m/s</span>²<span>) = 42 N</span>

 

Therefore:

<span>42 N = M (7 m/s</span>²)

<span>M = (42 N) / (7 m/s</span>²<span>)</span>

M = 6 kg mass of the second object

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Coordinate of position of y=3t^2+2

Time = 2.00 s

We need to calculate the acceleration

a = \dfrac{d^2x}{dt^2}

For x coordinates

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On differentiate again w.r.to t

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The acceleration in y axis at 2 sec

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The magnitude of the force

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|F|=180.89\ N

Hence, The net force acting on this object is 180.89 N.

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