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Anna35 [415]
3 years ago
8

1. You do not need to remove the lead weights inside tires before recycling them.

Engineering
1 answer:
makvit [3.9K]3 years ago
7 0
It true -.-.-.-.-.-.-.-.-.-.-.-.-.- EZ
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Which regulations are related to guard rail height and dimensions and uniformity of stairs?
galina1969 [7]

Answer:

C.

structural safety

Explanation:

Guards protecting floor surfaces must be 36 inches in height, while guards for stairs must be 34 inches in height measured vertically from the tread nosing. A guard may also serve as the required handrail (34 to 38 inches high) provided the top rail meets the requirements for grip size.

4 0
4 years ago
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It's in the picture please asap
Dennis_Churaev [7]
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3 years ago
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Sed is a multipurpose tool that combines the work of several filters. sed performs noninteractive operations on a data stream. s
timama [110]

Answer:

The answer is True.

Explanation:

SED is a command in UNIX for stream editors that parses and transforms text, using a simple, compact programming language. So the answer is TRUE that sed is a multipurpose tool that combines the work of several filters and performs noninteractive operations on a data stream. sed has a host of features that allow you ti select lines and run instructions on them.

6 0
3 years ago
The stress in the material of a pipe subject to internal pressure varies jointly with the internal pressure and the internal dia
aleksklad [387]

Answer:

The answer is 27.69 [psi]

Explanation:

(Barinly´s editor seem to not be working properly so please see attachment)

We know that:

  • σ≈\frac{P_{in} D_{in}}{t}

Where:

  • σ => Stress in the material
  • Pin => Internal Pressure
  • Din => Internal diameter
  • t => Thickness

Since we know that thre Stress is directly proportional to Pin and Din but inversely proportional to thickness, we need to add a proportionality constant "k" to our equation to make it complete:

  • σ=\frac{kP_{in} D_{in}}{t}

We also know that the Stress is 100 [psi] when Pin is 25 [psi], Din is 5 [in] and thickness is .75 [in], using this values we can solve for k:

  • k=\frac{σt}{P_{in}D_{in}  }

thus k = .6

Now all we need to know is use the same equation but using the new parameters: Pin = 15 [psi], Din = 2 [in] and t= .65 [in]

  • σ2 = \frac{(.6)(15)(2)}{.65}

The stress is 27.69 [psi]

6 0
3 years ago
What types of issues MAY occur to slow or prevent the best outcome?
german

Answer:

im sorry but i cant find any studies about this and im 3 days late

4 0
3 years ago
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