Answer:
a) 2.4 mm
b) 1.2 mm
c) 1.2 mm
Explanation:
To find the widths of the maxima you use the diffraction condition for destructive interference, given by the following formula:
a: width of the slit
λ: wavelength
m: order of the minimum
for little angles you have:
y: height of the mth minimum
a) the width of the central maximum is 2*y for m=1:
b) the width of first maximum is y2-y1:
c) and for the second maximum:
Answer:
1.6 pF
Explanation:
The capacitance of a parallel-plate capacitor in air is given by:
where
is the vacuum permittivity
A is the area of each plate
d is the separation between the plates
In this problem we have:
- Separation between the plates: d = 5.00 mm = 0.005 m
- Area of the plates:
Therefore, the capacitance is
To solve this problem we will apply the concepts related to the final volume of a body after undergoing a thermal expansion. To determine the temperature, we will use the given relationship as well as the theoretical value of the volumetric coefficient of thermal expansion of copper. This is, for example to the initial volume defined as , the relation with the final volume as
Initial temperature =
Let T be the temperature after expanding by the formula of volume expansion
we have,
Where is the volume coefficient of copper
Therefore the temperature is 53.06°C