Question

The potential difference between the plates of a parallel plate capacitor is 35 V and the electric field between the plates has a strength of 750 V/m. If the plate area is 4.0 Ý 10-2 m2, what is the capacitance of this capacitor?
a. 7.6 Ý 10-14 F
b. 7.6 Ý 10-10 F
c. 7.6 Ý 10-11 F
d. 7.6 Ý 10-12 F
e. None of the other choices is correct.

Answer 1

Answer:

Capacitance will be $7.6\times 10^{-12}F$

So option (d) will be correct option

Explanation:

We have given potential difference across the plate V = 35 volt

Electric field between the plate E = 750 volt/m

Area of the plate $a=4\times 10^{-2}m^2$

We have to find the capacitance

We know that potential difference is given by

$V=Ed$ here E is electric field and d is distance between the plate

So $35=75\times d$

d = 00466 m

We know that capacitance is given by

$C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 4\times 10^{-2}}{0.0466}=7.6\times 10^{-12}F$

So option (d) will be correct option